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| Description: If 𝑧 is not free in 𝜑, it is not free in [𝑦 / 𝑥]𝜑 when 𝑦 and 𝑧 are distinct. Version of hbsb 2529 with a disjoint variable condition, which requires fewer axioms. (Contributed by NM, 12-Aug-1993.) (Revised by GG, 23-May-2024.) (Proof shortened by Wolf Lammen, 14-May-2025.) | 
| Ref | Expression | 
|---|---|
| hbsbw.1 | ⊢ (𝜑 → ∀𝑧𝜑) | 
| Ref | Expression | 
|---|---|
| hbsbw | ⊢ ([𝑦 / 𝑥]𝜑 → ∀𝑧[𝑦 / 𝑥]𝜑) | 
| Step | Hyp | Ref | Expression | 
|---|---|---|---|
| 1 | hbsbw.1 | . . 3 ⊢ (𝜑 → ∀𝑧𝜑) | |
| 2 | 1 | sbimi 2074 | . 2 ⊢ ([𝑦 / 𝑥]𝜑 → [𝑦 / 𝑥]∀𝑧𝜑) | 
| 3 | sbal 2169 | . 2 ⊢ ([𝑦 / 𝑥]∀𝑧𝜑 ↔ ∀𝑧[𝑦 / 𝑥]𝜑) | |
| 4 | 2, 3 | sylib 218 | 1 ⊢ ([𝑦 / 𝑥]𝜑 → ∀𝑧[𝑦 / 𝑥]𝜑) | 
| Colors of variables: wff setvar class | 
| Syntax hints: → wi 4 ∀wal 1538 [wsb 2064 | 
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1795 ax-4 1809 ax-5 1910 ax-11 2157 | 
| This theorem depends on definitions: df-bi 207 df-ex 1780 df-sb 2065 | 
| This theorem is referenced by: nfsbv 2330 hbab 2725 hblem 2873 | 
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