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Mirrors > Home > MPE Home > Th. List > hbsbw | Structured version Visualization version GIF version |
Description: If 𝑧 is not free in 𝜑, it is not free in [𝑦 / 𝑥]𝜑 when 𝑦 and 𝑧 are distinct. Version of hbsb 2532 with a disjoint variable condition, which requires fewer axioms. (Contributed by NM, 12-Aug-1993.) (Revised by GG, 23-May-2024.) (Proof shortened by Wolf Lammen, 14-May-2025.) |
Ref | Expression |
---|---|
hbsbw.1 | ⊢ (𝜑 → ∀𝑧𝜑) |
Ref | Expression |
---|---|
hbsbw | ⊢ ([𝑦 / 𝑥]𝜑 → ∀𝑧[𝑦 / 𝑥]𝜑) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | hbsbw.1 | . . 3 ⊢ (𝜑 → ∀𝑧𝜑) | |
2 | 1 | sbimi 2074 | . 2 ⊢ ([𝑦 / 𝑥]𝜑 → [𝑦 / 𝑥]∀𝑧𝜑) |
3 | sbal 2170 | . 2 ⊢ ([𝑦 / 𝑥]∀𝑧𝜑 ↔ ∀𝑧[𝑦 / 𝑥]𝜑) | |
4 | 2, 3 | sylib 218 | 1 ⊢ ([𝑦 / 𝑥]𝜑 → ∀𝑧[𝑦 / 𝑥]𝜑) |
Colors of variables: wff setvar class |
Syntax hints: → wi 4 ∀wal 1535 [wsb 2064 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1793 ax-4 1807 ax-5 1909 ax-11 2158 |
This theorem depends on definitions: df-bi 207 df-ex 1778 df-sb 2065 |
This theorem is referenced by: nfsbv 2334 hbab 2728 hblem 2876 |
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