Theorem nfnf 2356

Description: If 𝑥 is not free in 𝜑, then it is not free in Ⅎ𝑦𝜑. (Contributed by Mario Carneiro, 11-Aug-2016.) (Proof shortened by Wolf Lammen, 30-Dec-2017.)

Hypothesis

Ref	Expression
nfnf.1	⊢ Ⅎ𝑥𝜑

Assertion

Ref	Expression
nfnf	⊢ Ⅎ𝑥Ⅎ𝑦𝜑

Proof of Theorem nfnf

Step	Hyp	Ref	Expression
1		df-nf 1816	. 2 ⊢ (Ⅎ𝑦𝜑 ↔ (∃𝑦𝜑 → ∀𝑦𝜑))
2		nfnf.1	. . . 4 ⊢ Ⅎ𝑥𝜑
3	2	nfex 2354	. . 3 ⊢ Ⅎ𝑥∃𝑦𝜑
4	2	nfal 2353	. . 3 ⊢ Ⅎ𝑥∀𝑦𝜑
5	3, 4	nfim 1928	. 2 ⊢ Ⅎ𝑥(∃𝑦𝜑 → ∀𝑦𝜑)
6	1, 5	nfxfr 1885	1 ⊢ Ⅎ𝑥Ⅎ𝑦𝜑

This proof depends on syntax axioms:   → wi 4  ∀wal 1567  ∃wex 1811  Ⅎwnf 1815

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-10 2177  ax-11 2193  ax-12 2212

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-ex 1812  df-nf 1816

This theorem is used by:  nfnfc  2934  bj-nfcf  37910