Theorem nfnf 2361

Description: If 𝑥 is not free in 𝜑, then it is not free in Ⅎ𝑦𝜑. (Contributed by Mario Carneiro, 11-Aug-2016.) (Proof shortened by Wolf Lammen, 30-Dec-2017.)

Hypothesis

Ref	Expression
nfnf.1	⊢ Ⅎ𝑥𝜑

Assertion

Ref	Expression
nfnf	⊢ Ⅎ𝑥Ⅎ𝑦𝜑

Proof of Theorem nfnf

Step	Hyp	Ref	Expression
1		df-nf 1817	. 2 ⊢ (Ⅎ𝑦𝜑 ↔ (∃𝑦𝜑 → ∀𝑦𝜑))
2		nfnf.1	. . . 4 ⊢ Ⅎ𝑥𝜑
3	2	nfex 2359	. . 3 ⊢ Ⅎ𝑥∃𝑦𝜑
4	2	nfal 2358	. . 3 ⊢ Ⅎ𝑥∀𝑦𝜑
5	3, 4	nfim 1929	. 2 ⊢ Ⅎ𝑥(∃𝑦𝜑 → ∀𝑦𝜑)
6	1, 5	nfxfr 1886	1 ⊢ Ⅎ𝑥Ⅎ𝑦𝜑

This proof depends on syntax axioms:   → wi 4  ∀wal 1568  ∃wex 1812  Ⅎwnf 1816

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-10 2179  ax-11 2195  ax-12 2216

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-ex 1813  df-nf 1817

This theorem is used by:  nfnfc  2939  bj-nfcf  37617