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Theorem nfrmo1 3393
Description: The setvar 𝑥 is not free in ∃*𝑥 ∈ 𝐴𝜑. (Contributed by NM, 16-Jun-2017.)
Assertion
Ref Expression
nfrmo1 Ⅎ𝑥∃*𝑥 ∈ 𝐴 𝜑

Proof of Theorem nfrmo1
StepHypRef Expression
1 df-rmo 3366 . 2 (∃*𝑥 ∈ 𝐴 𝜑 ↔ ∃*𝑥(𝑥 ∈ 𝐴 ∧ 𝜑))
2 nfmo1 2583 . 2 Ⅎ𝑥∃*𝑥(𝑥 ∈ 𝐴 ∧ 𝜑)
31, 2nfxfr 1886 1 Ⅎ𝑥∃*𝑥 ∈ 𝐴 𝜑
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   ∧ wa 401  Ⅎwnf 1816   ∈ wcel 2145  ∃*wmo 2563  ∃*wrmo 3365
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-10 2178  ax-11 2194
This proof depends on definitions:  df-bi 210  df-an 402  df-ex 1813  df-nf 1817  df-mo 2565  df-rmo 3366
This theorem is used by:  nfdisj1  5084  2reu3  48179
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