Theorem eqimssi 3148

Description: Infer subclass relationship from equality. (Contributed by NM, 6-Jan-2007.)

Hypothesis

Ref	Expression
eqimssi.1	|- A = B

Assertion

Ref	Expression
eqimssi	|- A C_ B

Proof of Theorem eqimssi

Step	Hyp	Ref	Expression
1		ssid 3112	. 2 |- A C_ A
2		eqimssi.1	. 2 |- A = B
3	1, 2	sseqtri 3126	1 |- A C_ B

Syntax hints:   = wceq 1331   C_ wss 3066

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1423  ax-7 1424  ax-gen 1425  ax-ie1 1469  ax-ie2 1470  ax-8 1482  ax-11 1484  ax-4 1487  ax-17 1506  ax-i9 1510  ax-ial 1514  ax-i5r 1515  ax-ext 2119

This theorem depends on definitions:  df-bi 116  df-nf 1437  df-sb 1736  df-clab 2124  df-cleq 2130  df-clel 2133  df-in 3072  df-ss 3079

This theorem is referenced by:  funi  5150  fpr  5595  elfzo1  9960  sumsplitdc  11194  isumlessdc  11258