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Theorem ifnetruedc 3602
Description: Deduce truth from a conditional operator value. (Contributed by Thierry Arnoux, 20-Feb-2025.)
Assertion
Ref Expression
ifnetruedc  |-  ( (DECID  ph  /\  A  =/=  B  /\  if ( ph ,  A ,  B )  =  A )  ->  ph )

Proof of Theorem ifnetruedc
StepHypRef Expression
1 simp1 999 . 2  |-  ( (DECID  ph  /\  A  =/=  B  /\  if ( ph ,  A ,  B )  =  A )  -> DECID  ph )
2 iffalse 3569 . . . 4  |-  ( -. 
ph  ->  if ( ph ,  A ,  B )  =  B )
32adantl 277 . . 3  |-  ( ( (DECID 
ph  /\  A  =/=  B  /\  if ( ph ,  A ,  B )  =  A )  /\  -.  ph )  ->  if ( ph ,  A ,  B )  =  B )
4 simpl3 1004 . . . . 5  |-  ( ( (DECID 
ph  /\  A  =/=  B  /\  if ( ph ,  A ,  B )  =  A )  /\  -.  ph )  ->  if ( ph ,  A ,  B )  =  A )
5 simpl2 1003 . . . . 5  |-  ( ( (DECID 
ph  /\  A  =/=  B  /\  if ( ph ,  A ,  B )  =  A )  /\  -.  ph )  ->  A  =/=  B )
64, 5eqnetrd 2391 . . . 4  |-  ( ( (DECID 
ph  /\  A  =/=  B  /\  if ( ph ,  A ,  B )  =  A )  /\  -.  ph )  ->  if ( ph ,  A ,  B )  =/=  B
)
76neneqd 2388 . . 3  |-  ( ( (DECID 
ph  /\  A  =/=  B  /\  if ( ph ,  A ,  B )  =  A )  /\  -.  ph )  ->  -.  if ( ph ,  A ,  B )  =  B )
83, 7condandc 882 . 2  |-  (DECID  ph  ->  ( (DECID 
ph  /\  A  =/=  B  /\  if ( ph ,  A ,  B )  =  A )  ->  ph ) )
91, 8mpcom 36 1  |-  ( (DECID  ph  /\  A  =/=  B  /\  if ( ph ,  A ,  B )  =  A )  ->  ph )
Colors of variables: wff set class
Syntax hints:   -. wn 3    -> wi 4    /\ wa 104  DECID wdc 835    /\ w3a 980    = wceq 1364    =/= wne 2367   ifcif 3561
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 615  ax-in2 616  ax-io 710  ax-5 1461  ax-7 1462  ax-gen 1463  ax-ie1 1507  ax-ie2 1508  ax-8 1518  ax-11 1520  ax-4 1524  ax-17 1540  ax-i9 1544  ax-ial 1548  ax-i5r 1549  ax-ext 2178
This theorem depends on definitions:  df-bi 117  df-dc 836  df-3an 982  df-nf 1475  df-sb 1777  df-clab 2183  df-cleq 2189  df-clel 2192  df-ne 2368  df-if 3562
This theorem is referenced by:  ifnebibdc  3604
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