Theorem eqnetrd 2424

Description: Substitution of equal classes into an inequality. (Contributed by NM, 4-Jul-2012.)

Hypotheses

Ref	Expression
eqnetrd.1	|- ( ph -> A = B )
eqnetrd.2	|- ( ph -> B =/= C )

Assertion

Ref	Expression
eqnetrd	|- ( ph -> A =/= C )

Proof of Theorem eqnetrd

Step	Hyp	Ref	Expression
1		eqnetrd.2	. 2 |- ( ph -> B =/= C )
2		eqnetrd.1	. . 3 |- ( ph -> A = B )
3	2	neeq1d 2418	. 2 |- ( ph -> ( A =/= C <-> B =/= C ) )
4	1, 3	mpbird 167	1 |- ( ph -> A =/= C )

Syntax hints:   -> wi 4   = wceq 1395   =/= wne 2400

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 617  ax-in2 618  ax-5 1493  ax-gen 1495  ax-4 1556  ax-17 1572  ax-ext 2211

This theorem depends on definitions:  df-bi 117  df-cleq 2222  df-ne 2401

This theorem is referenced by:  eqnetrrd  2426  ifnetruedc  3646  ifnefals  3647  frecabcl  6551  frecsuclem  6558  omp1eomlem  7272  xaddnemnf  10065  xaddnepnf  10066  hashprg  11043  bezoutr1  12570  phibndlem  12754  dfphi2  12758  lgsne0  15733  2sqlem8a  15817  2sqlem8  15818