Theorem eqnetrd 2402

Description: Substitution of equal classes into an inequality. (Contributed by NM, 4-Jul-2012.)

Hypotheses

Ref	Expression
eqnetrd.1	|- ( ph -> A = B )
eqnetrd.2	|- ( ph -> B =/= C )

Assertion

Ref	Expression
eqnetrd	|- ( ph -> A =/= C )

Proof of Theorem eqnetrd

Step	Hyp	Ref	Expression
1		eqnetrd.2	. 2 |- ( ph -> B =/= C )
2		eqnetrd.1	. . 3 |- ( ph -> A = B )
3	2	neeq1d 2396	. 2 |- ( ph -> ( A =/= C <-> B =/= C ) )
4	1, 3	mpbird 167	1 |- ( ph -> A =/= C )

Syntax hints:   -> wi 4   = wceq 1373   =/= wne 2378

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 615  ax-in2 616  ax-5 1471  ax-gen 1473  ax-4 1534  ax-17 1550  ax-ext 2189

This theorem depends on definitions:  df-bi 117  df-cleq 2200  df-ne 2379

This theorem is referenced by:  eqnetrrd  2404  ifnetruedc  3623  ifnefals  3624  frecabcl  6508  frecsuclem  6515  omp1eomlem  7222  xaddnemnf  10014  xaddnepnf  10015  hashprg  10990  bezoutr1  12469  phibndlem  12653  dfphi2  12657  lgsne0  15630  2sqlem8a  15714  2sqlem8  15715