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Theorem pwpwpw0ss 3770
Description: Compute the power set of the power set of the power set of the empty set. (See also pw0 3703 and pwpw0ss 3767.) (Contributed by Jim Kingdon, 13-Aug-2018.)
Assertion
Ref Expression
pwpwpw0ss  |-  ( {
(/) ,  { (/) } }  u.  { { { (/) } } ,  { (/) ,  { (/) } } }
)  C_  ~P { (/) ,  { (/) } }

Proof of Theorem pwpwpw0ss
StepHypRef Expression
1 pwprss 3768 1  |-  ( {
(/) ,  { (/) } }  u.  { { { (/) } } ,  { (/) ,  { (/) } } }
)  C_  ~P { (/) ,  { (/) } }
Colors of variables: wff set class
Syntax hints:    u. cun 3100    C_ wss 3102   (/)c0 3394   ~Pcpw 3543   {csn 3560   {cpr 3561
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-in1 604  ax-in2 605  ax-io 699  ax-5 1427  ax-7 1428  ax-gen 1429  ax-ie1 1473  ax-ie2 1474  ax-8 1484  ax-10 1485  ax-11 1486  ax-i12 1487  ax-bndl 1489  ax-4 1490  ax-17 1506  ax-i9 1510  ax-ial 1514  ax-i5r 1515  ax-ext 2139
This theorem depends on definitions:  df-bi 116  df-tru 1338  df-nf 1441  df-sb 1743  df-clab 2144  df-cleq 2150  df-clel 2153  df-nfc 2288  df-v 2714  df-dif 3104  df-un 3106  df-in 3108  df-ss 3115  df-nul 3395  df-pw 3545  df-sn 3566  df-pr 3567
This theorem is referenced by: (None)
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