Theorem pwpw0ss 3726

Description: Compute the power set of the power set of the empty set. (See pw0 3662 for the power set of the empty set.) Theorem 90 of [Suppes] p. 48 (but with subset in place of equality). (Contributed by Jim Kingdon, 12-Aug-2018.)

Assertion

Ref	Expression
pwpw0ss	|- { (/) , { (/) } } C_ ~P { (/) }

Proof of Theorem pwpw0ss

Step	Hyp	Ref	Expression
1		pwsnss 3725	1 |- { (/) , { (/) } } C_ ~P { (/) }

Syntax hints:   C_ wss 3066   (/)c0 3358   ~Pcpw 3505   {csn 3522   {cpr 3523

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-in1 603  ax-in2 604  ax-io 698  ax-5 1423  ax-7 1424  ax-gen 1425  ax-ie1 1469  ax-ie2 1470  ax-8 1482  ax-10 1483  ax-11 1484  ax-i12 1485  ax-bndl 1486  ax-4 1487  ax-17 1506  ax-i9 1510  ax-ial 1514  ax-i5r 1515  ax-ext 2119

This theorem depends on definitions:  df-bi 116  df-tru 1334  df-nf 1437  df-sb 1736  df-clab 2124  df-cleq 2130  df-clel 2133  df-nfc 2268  df-v 2683  df-dif 3068  df-un 3070  df-in 3072  df-ss 3079  df-nul 3359  df-pw 3507  df-sn 3528  df-pr 3529

This theorem is referenced by:  pp0ex  4108  exmidpw  6795  pw1dom2  13179