Theorem sbanv 1889

Description: Version of sban 1955 where x and y are distinct. (Contributed by Jim Kingdon, 24-Dec-2017.)

Assertion

Ref	Expression
sbanv	|- ( [ y / x ] ( ph /\ ps ) <-> ( [ y / x ] ph /\ [ y / x ] ps ) )

Distinct variable group:   x, y

Allowed substitution hints:   ph( x, y)   ps( x, y)

Proof of Theorem sbanv

Step	Hyp	Ref	Expression
1		sb6 1886	. 2 |- ( [ y / x ] ( ph /\ ps ) <-> A. x ( x = y -> ( ph /\ ps ) ) )
2		sb6 1886	. . . 4 |- ( [ y / x ] ph <-> A. x ( x = y -> ph ) )
3		sb6 1886	. . . 4 |- ( [ y / x ] ps <-> A. x ( x = y -> ps ) )
4	2, 3	anbi12i 460	. . 3 |- ( ( [ y / x ] ph /\ [ y / x ] ps ) <-> ( A. x ( x = y -> ph ) /\ A. x ( x = y -> ps ) ) )
5		19.26 1481	. . 3 |- ( A. x ( ( x = y -> ph ) /\ ( x = y -> ps ) ) <-> ( A. x ( x = y -> ph ) /\ A. x ( x = y -> ps ) ) )
6		pm4.76 604	. . . 4 |- ( ( ( x = y -> ph ) /\ ( x = y -> ps ) ) <-> ( x = y -> ( ph /\ ps ) ) )
7	6	albii 1470	. . 3 |- ( A. x ( ( x = y -> ph ) /\ ( x = y -> ps ) ) <-> A. x ( x = y -> ( ph /\ ps ) ) )
8	4, 5, 7	3bitr2i 208	. 2 |- ( ( [ y / x ] ph /\ [ y / x ] ps ) <-> A. x ( x = y -> ( ph /\ ps ) ) )
9	1, 8	bitr4i 187	1 |- ( [ y / x ] ( ph /\ ps ) <-> ( [ y / x ] ph /\ [ y / x ] ps ) )

Syntax hints:   -> wi 4   /\ wa 104   <-> wb 105   A.wal 1351   [wsb 1762

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1447  ax-gen 1449  ax-ie1 1493  ax-ie2 1494  ax-8 1504  ax-11 1506  ax-4 1510  ax-17 1526  ax-i9 1530  ax-ial 1534

This theorem depends on definitions:  df-bi 117  df-sb 1763

This theorem is referenced by:  sban  1955