Theorem feq2i 5378

Description: Equality inference for functions. (Contributed by NM, 5-Sep-2011.)

Hypothesis

Ref	Expression
feq2i.1	⊢ 𝐴 = 𝐵

Assertion

Ref	Expression
feq2i	⊢ (𝐹:𝐴⟶𝐶 ↔ 𝐹:𝐵⟶𝐶)

Proof of Theorem feq2i

Step	Hyp	Ref	Expression
1		feq2i.1	. 2 ⊢ 𝐴 = 𝐵
2		feq2 5368	. 2 ⊢ (𝐴 = 𝐵 → (𝐹:𝐴⟶𝐶 ↔ 𝐹:𝐵⟶𝐶))
3	1, 2	ax-mp 5	1 ⊢ (𝐹:𝐴⟶𝐶 ↔ 𝐹:𝐵⟶𝐶)

Syntax hints:   ↔ wb 105   = wceq 1364  ⟶wf 5231

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1458  ax-gen 1460  ax-4 1521  ax-17 1537  ax-ext 2171

This theorem depends on definitions:  df-bi 117  df-cleq 2182  df-fn 5238  df-f 5239

This theorem is referenced by:  fmpox  6225  fmpo  6226  tposf  6297  issmo  6313  tfrcllemsucfn  6378  1fv  10169  fxnn0nninf  10469  0met  14344  dvef  14648