Theorem sepgi 4252

Description: Inference associated with sepg 4251. (Contributed by NM, 21-Jun-1993.) (Revised by BJ, 14-Jul-2026.)

Hypothesis

Ref	Expression
sepgi.1	⊢ 𝐴 ∈ V

Assertion

Ref	Expression
sepgi	⊢ ∃𝑦∀𝑥(𝑥 ∈ 𝑦 ↔ (𝑥 ∈ 𝐴 ∧ 𝜑))

Distinct variable groups:   𝑥,𝐴,𝑦   𝜑,𝑦

Allowed substitution hint:   𝜑(𝑥)

Proof of Theorem sepgi

Step	Hyp	Ref	Expression
1		sepgi.1	. 2 ⊢ 𝐴 ∈ V
2		sepg 4251	. 2 ⊢ (𝐴 ∈ V → ∃𝑦∀𝑥(𝑥 ∈ 𝑦 ↔ (𝑥 ∈ 𝐴 ∧ 𝜑)))
3	1, 2	ax-mp 5	1 ⊢ ∃𝑦∀𝑥(𝑥 ∈ 𝑦 ↔ (𝑥 ∈ 𝐴 ∧ 𝜑))

This proof depends on syntax axioms:   ∧ wa 104   ↔ wb 105  ∀wal 1400  ∃wex 1545   ∈ wcel 2209  Vcvv 2821

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 721  ax-5 1500  ax-7 1501  ax-gen 1502  ax-ie1 1546  ax-ie2 1547  ax-8 1557  ax-10 1558  ax-11 1559  ax-i12 1560  ax-bndl 1562  ax-4 1563  ax-17 1579  ax-i9 1583  ax-ial 1587  ax-i5r 1588  ax-ext 2220  ax-sep 4249

This proof depends on definitions:  df-bi 117  df-tru 1405  df-nf 1514  df-sb 1816  df-clab 2225  df-cleq 2231  df-clel 2234  df-nfc 2381  df-v 2823

This theorem is used by:  inex1  4267  bj-d0clsepcl  16951