Theorem sylan9req 2292

Description: An equality transitivity deduction. (Contributed by NM, 23-Jun-2007.)

Hypotheses

Ref	Expression
sylan9req.1	⊢ (𝜑 → 𝐵 = 𝐴)
sylan9req.2	⊢ (𝜓 → 𝐵 = 𝐶)

Assertion

Ref	Expression
sylan9req	⊢ ((𝜑 ∧ 𝜓) → 𝐴 = 𝐶)

Proof of Theorem sylan9req

Step	Hyp	Ref	Expression
1		sylan9req.1	. . 3 ⊢ (𝜑 → 𝐵 = 𝐴)
2	1	eqcomd 2244	. 2 ⊢ (𝜑 → 𝐴 = 𝐵)
3		sylan9req.2	. 2 ⊢ (𝜓 → 𝐵 = 𝐶)
4	2, 3	sylan9eq 2291	1 ⊢ ((𝜑 ∧ 𝜓) → 𝐴 = 𝐶)

This proof depends on syntax axioms:   → wi 4   ∧ wa 104   = wceq 1402

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1500  ax-gen 1502  ax-4 1563  ax-17 1579  ax-ext 2220

This proof depends on definitions:  df-bi 117  df-cleq 2231

This theorem is used by:  fndmu  5487  fodmrnu  5626  funcoeqres  5673  fvunsng  5912  mapsnd  6975  prarloclem5  7874  addlocprlemeq  7907  zdiv  9746  resqrexlemnm  11807  fprodssdc  12383  dvdsmulc  12612  cncongrcoprm  12910  mgmidmo  13752  lgsmodeq  16381