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Theorem 3unrab 32827
Description: Union of three restricted class abstractions. (Contributed by Thierry Arnoux, 6-Jul-2025.)
Assertion
Ref Expression
3unrab (({𝑥𝐴𝜑} ∪ {𝑥𝐴𝜓}) ∪ {𝑥𝐴𝜒}) = {𝑥𝐴 ∣ (𝜑𝜓𝜒)}

Proof of Theorem 3unrab
StepHypRef Expression
1 unrab 4269 . 2 ({𝑥𝐴 ∣ (𝜑𝜓)} ∪ {𝑥𝐴𝜒}) = {𝑥𝐴 ∣ ((𝜑𝜓) ∨ 𝜒)}
2 unrab 4269 . . 3 ({𝑥𝐴𝜑} ∪ {𝑥𝐴𝜓}) = {𝑥𝐴 ∣ (𝜑𝜓)}
32uneq1i 4119 . 2 (({𝑥𝐴𝜑} ∪ {𝑥𝐴𝜓}) ∪ {𝑥𝐴𝜒}) = ({𝑥𝐴 ∣ (𝜑𝜓)} ∪ {𝑥𝐴𝜒})
4 df-3or 1104 . . 3 ((𝜑𝜓𝜒) ↔ ((𝜑𝜓) ∨ 𝜒))
54rabbii 3421 . 2 {𝑥𝐴 ∣ (𝜑𝜓𝜒)} = {𝑥𝐴 ∣ ((𝜑𝜓) ∨ 𝜒)}
61, 3, 53eqtr4i 2796 1 (({𝑥𝐴𝜑} ∪ {𝑥𝐴𝜓}) ∪ {𝑥𝐴𝜒}) = {𝑥𝐴 ∣ (𝜑𝜓𝜒)}
Colors of variables: wff setvar class
Syntax hints:  wo 860  w3o 1102   = wceq 1570  {crab 3416  cun 3904
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1825  ax-4 1839  ax-5 1940  ax-6 1997  ax-7 2038  ax-8 2145  ax-9 2153  ax-10 2176  ax-12 2213  ax-ext 2735
This theorem depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3or 1104  df-tru 1573  df-ex 1810  df-nf 1814  df-sb 2097  df-clab 2742  df-cleq 2755  df-clel 2838  df-rab 3417  df-v 3457  df-un 3911
This theorem is referenced by:  constrfin  34114
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