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Theorem bj-elabd2ALT 37808
Description: Alternate proof of elabd2 3624 bypassing elab6g 3623 (and using sbiedvw 2132 instead of the ∀𝑥(𝑥 = 𝑦 → 𝜓) idiom). (Contributed by BJ, 16-Oct-2024.) (Proof modification is discouraged.) (New usage is discouraged.)
Hypotheses
Ref Expression
bj-elabd2ALT.ex (𝜑 → 𝐴 ∈ 𝑉)
bj-elabd2ALT.eq (𝜑 → 𝐵 = {𝑥 ∣ 𝜓})
bj-elabd2ALT.is ((𝜑 ∧ 𝑥 = 𝐴) → (𝜓 ↔ 𝜒))
Assertion
Ref Expression
bj-elabd2ALT (𝜑 → (𝐴 ∈ 𝐵 ↔ 𝜒))
Distinct variable groups:   𝜑,𝑥   𝜒,𝑥   𝑥,𝐴
Allowed substitution hints:   𝜓(𝑥)   𝐵(𝑥)   𝑉(𝑥)

Proof of Theorem bj-elabd2ALT
Dummy variable 𝑦 is distinct from all other variables.
StepHypRef Expression
1 bj-elabd2ALT.ex . 2 (𝜑 → 𝐴 ∈ 𝑉)
2 simpr 490 . . . 4 ((𝜑 ∧ 𝑦 = 𝐴) → 𝑦 = 𝐴)
3 bj-elabd2ALT.eq . . . . . 6 (𝜑 → 𝐵 = {𝑥 ∣ 𝜓})
43eqcomd 2767 . . . . 5 (𝜑 → {𝑥 ∣ 𝜓} = 𝐵)
54adantr 486 . . . 4 ((𝜑 ∧ 𝑦 = 𝐴) → {𝑥 ∣ 𝜓} = 𝐵)
62, 5eleq12d 2855 . . 3 ((𝜑 ∧ 𝑦 = 𝐴) → (𝑦 ∈ {𝑥 ∣ 𝜓} ↔ 𝐴 ∈ 𝐵))
7 eqeq1 2765 . . . . . . . 8 (𝑥 = 𝑦 → (𝑥 = 𝐴 ↔ 𝑦 = 𝐴))
87biimparc 485 . . . . . . 7 ((𝑦 = 𝐴 ∧ 𝑥 = 𝑦) → 𝑥 = 𝐴)
98anim2i 629 . . . . . 6 ((𝜑 ∧ (𝑦 = 𝐴 ∧ 𝑥 = 𝑦)) → (𝜑 ∧ 𝑥 = 𝐴))
109anassrs 473 . . . . 5 (((𝜑 ∧ 𝑦 = 𝐴) ∧ 𝑥 = 𝑦) → (𝜑 ∧ 𝑥 = 𝐴))
11 bj-elabd2ALT.is . . . . 5 ((𝜑 ∧ 𝑥 = 𝐴) → (𝜓 ↔ 𝜒))
1210, 11syl 18 . . . 4 (((𝜑 ∧ 𝑦 = 𝐴) ∧ 𝑥 = 𝑦) → (𝜓 ↔ 𝜒))
1312sbiedvw 2132 . . 3 ((𝜑 ∧ 𝑦 = 𝐴) → ([𝑦 / 𝑥]𝜓 ↔ 𝜒))
146, 13bibi12d 348 . 2 ((𝜑 ∧ 𝑦 = 𝐴) → ((𝑦 ∈ {𝑥 ∣ 𝜓} ↔ [𝑦 / 𝑥]𝜓) ↔ (𝐴 ∈ 𝐵 ↔ 𝜒)))
15 df-clab 2740 . . 3 (𝑦 ∈ {𝑥 ∣ 𝜓} ↔ [𝑦 / 𝑥]𝜓)
1615a1i 11 . 2 (𝜑 → (𝑦 ∈ {𝑥 ∣ 𝜓} ↔ [𝑦 / 𝑥]𝜓))
171, 14, 16vtocld 3523 1 (𝜑 → (𝐴 ∈ 𝐵 ↔ 𝜒))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ↔ wb 209   ∧ wa 401   = wceq 1570  [wsb 2099   ∈ wcel 2145  {cab 2739
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2733
This proof depends on definitions:  df-bi 210  df-an 402  df-tru 1573  df-ex 1813  df-sb 2100  df-clab 2740  df-cleq 2753  df-clel 2836
This theorem is used by: (None)
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