Theorem bj-snfromadj 37927

Description: Singleton from adjunction and empty set. (Contributed by BJ, 19-Jan-2025.) (Proof modification is discouraged.)

Assertion

Ref	Expression
bj-snfromadj	⊢ {𝑥} ∈ V

Proof of Theorem bj-snfromadj

Step	Hyp	Ref	Expression
1		0un 4346	. 2 ⊢ (∅ ∪ {𝑥}) = {𝑥}
2		0ex 5261	. . 3 ⊢ ∅ ∈ V
3		bj-adjg1 37926	. . 3 ⊢ (∅ ∈ V → (∅ ∪ {𝑥}) ∈ V)
4	2, 3	ax-mp 5	. 2 ⊢ (∅ ∪ {𝑥}) ∈ V
5	1, 4	eqeltrri 2858	1 ⊢ {𝑥} ∈ V

This proof depends on syntax axioms:   ∈ wcel 2145  Vcvv 3451   ∪ cun 3897  ∅c0 4279  {csn 4584

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-12 2213  ax-ext 2733  ax-nul 5260  ax-bj-adj 37925

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2100  df-clab 2740  df-cleq 2753  df-clel 2836  df-v 3453  df-dif 3902  df-un 3904  df-nul 4280  df-sn 4585

This theorem is used by:  bj-prfromadj  37928