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Theorem cbvcsbv 3858
Description: Change the bound variable of a proper substitution into a class using implicit substitution. (Contributed by NM, 30-Sep-2008.) (Revised by Mario Carneiro, 13-Oct-2016.)
Hypothesis
Ref Expression
cbvcsbv.1 (𝑥 = 𝑦 → 𝐵 = 𝐶)
Assertion
Ref Expression
cbvcsbv ⦋𝐴 / 𝑥⦌𝐵 = ⦋𝐴 / 𝑦⦌𝐶
Distinct variable groups:   𝑥,𝑦   𝑦,𝐵   𝑥,𝐶
Allowed substitution hints:   𝐴(𝑥, 𝑦)   𝐵(𝑥)   𝐶(𝑦)

Proof of Theorem cbvcsbv
Dummy variable 𝑧 is distinct from all other variables.
StepHypRef Expression
1 cbvcsbv.1 . . . . 5 (𝑥 = 𝑦 → 𝐵 = 𝐶)
21eleq2d 2846 . . . 4 (𝑥 = 𝑦 → (𝑧 ∈ 𝐵 ↔ 𝑧 ∈ 𝐶))
32cbvsbcvw 3772 . . 3 ([𝐴 / 𝑥]𝑧 ∈ 𝐵 ↔ [𝐴 / 𝑦]𝑧 ∈ 𝐶)
43abbii 2827 . 2 {𝑧 ∣ [𝐴 / 𝑥]𝑧 ∈ 𝐵} = {𝑧 ∣ [𝐴 / 𝑦]𝑧 ∈ 𝐶}
5 df-csb 3847 . 2 ⦋𝐴 / 𝑥⦌𝐵 = {𝑧 ∣ [𝐴 / 𝑥]𝑧 ∈ 𝐵}
6 df-csb 3847 . 2 ⦋𝐴 / 𝑦⦌𝐶 = {𝑧 ∣ [𝐴 / 𝑦]𝑧 ∈ 𝐶}
74, 5, 63eqtr4i 2793 1 ⦋𝐴 / 𝑥⦌𝐵 = ⦋𝐴 / 𝑦⦌𝐶
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   = wceq 1569   ∈ wcel 2144  {cab 2738  [wsbc 3738  ⦋csb 3846
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-ext 2732
This proof depends on definitions:  df-bi 210  df-an 402  df-ex 1812  df-sb 2099  df-clab 2739  df-cleq 2752  df-clel 2835  df-sbc 3739  df-csb 3847
This theorem is used by:  cbvsumv  15868  cbvprodv  16088  pmatcollpw3lem  23106  precsexlemcbv  28597  cbvprodvw2  37128  poimirlem27  38658  cdleme40v  41619
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