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Type | Label | Description |
---|---|---|
Statement | ||
Theorem | csbeq12dv 3901* | Formula-building inference for class substitution. (Contributed by SN, 3-Nov-2023.) |
⊢ (𝜑 → 𝐴 = 𝐶) & ⊢ (𝜑 → 𝐵 = 𝐷) ⇒ ⊢ (𝜑 → ⦋𝐴 / 𝑥⦌𝐵 = ⦋𝐶 / 𝑥⦌𝐷) | ||
Theorem | cbvcsbw 3902* | Change bound variables in a class substitution. Interestingly, this does not require any bound variable conditions on 𝐴. Version of cbvcsb 3903 with a disjoint variable condition, which does not require ax-13 2369. (Contributed by Jeff Hankins, 13-Sep-2009.) Avoid ax-13 2369. (Revised by Gino Giotto, 10-Jan-2024.) |
⊢ Ⅎ𝑦𝐶 & ⊢ Ⅎ𝑥𝐷 & ⊢ (𝑥 = 𝑦 → 𝐶 = 𝐷) ⇒ ⊢ ⦋𝐴 / 𝑥⦌𝐶 = ⦋𝐴 / 𝑦⦌𝐷 | ||
Theorem | cbvcsb 3903 | Change bound variables in a class substitution. Interestingly, this does not require any bound variable conditions on 𝐴. Usage of this theorem is discouraged because it depends on ax-13 2369. Use the weaker cbvcsbw 3902 when possible. (Contributed by Jeff Hankins, 13-Sep-2009.) (Revised by Mario Carneiro, 11-Dec-2016.) (New usage is discouraged.) |
⊢ Ⅎ𝑦𝐶 & ⊢ Ⅎ𝑥𝐷 & ⊢ (𝑥 = 𝑦 → 𝐶 = 𝐷) ⇒ ⊢ ⦋𝐴 / 𝑥⦌𝐶 = ⦋𝐴 / 𝑦⦌𝐷 | ||
Theorem | cbvcsbv 3904* | Change the bound variable of a proper substitution into a class using implicit substitution. (Contributed by NM, 30-Sep-2008.) (Revised by Mario Carneiro, 13-Oct-2016.) |
⊢ (𝑥 = 𝑦 → 𝐵 = 𝐶) ⇒ ⊢ ⦋𝐴 / 𝑥⦌𝐵 = ⦋𝐴 / 𝑦⦌𝐶 | ||
Theorem | csbid 3905 | Analogue of sbid 2245 for proper substitution into a class. (Contributed by NM, 10-Nov-2005.) |
⊢ ⦋𝑥 / 𝑥⦌𝐴 = 𝐴 | ||
Theorem | csbeq1a 3906 | Equality theorem for proper substitution into a class. (Contributed by NM, 10-Nov-2005.) |
⊢ (𝑥 = 𝐴 → 𝐵 = ⦋𝐴 / 𝑥⦌𝐵) | ||
Theorem | csbcow 3907* | Composition law for chained substitutions into a class. Version of csbco 3908 with a disjoint variable condition, which does not require ax-13 2369. (Contributed by NM, 10-Nov-2005.) Avoid ax-13 2369. (Revised by Gino Giotto, 10-Jan-2024.) |
⊢ ⦋𝐴 / 𝑦⦌⦋𝑦 / 𝑥⦌𝐵 = ⦋𝐴 / 𝑥⦌𝐵 | ||
Theorem | csbco 3908* | Composition law for chained substitutions into a class. Usage of this theorem is discouraged because it depends on ax-13 2369. Use the weaker csbcow 3907 when possible. (Contributed by NM, 10-Nov-2005.) (New usage is discouraged.) |
⊢ ⦋𝐴 / 𝑦⦌⦋𝑦 / 𝑥⦌𝐵 = ⦋𝐴 / 𝑥⦌𝐵 | ||
Theorem | csbtt 3909 | Substitution doesn't affect a constant 𝐵 (in which 𝑥 is not free). (Contributed by Mario Carneiro, 14-Oct-2016.) |
⊢ ((𝐴 ∈ 𝑉 ∧ Ⅎ𝑥𝐵) → ⦋𝐴 / 𝑥⦌𝐵 = 𝐵) | ||
Theorem | csbconstgf 3910 | Substitution doesn't affect a constant 𝐵 (in which 𝑥 is not free). (Contributed by NM, 10-Nov-2005.) |
⊢ Ⅎ𝑥𝐵 ⇒ ⊢ (𝐴 ∈ 𝑉 → ⦋𝐴 / 𝑥⦌𝐵 = 𝐵) | ||
Theorem | csbconstg 3911* | Substitution doesn't affect a constant 𝐵 (in which 𝑥 does not occur). csbconstgf 3910 with distinct variable requirement. (Contributed by Alan Sare, 22-Jul-2012.) Avoid ax-12 2169. (Revised by Gino Giotto, 15-Oct-2024.) |
⊢ (𝐴 ∈ 𝑉 → ⦋𝐴 / 𝑥⦌𝐵 = 𝐵) | ||
Theorem | csbconstgOLD 3912* | Obsolete version of csbconstg 3911 as of 15-Oct-2024. (Contributed by Alan Sare, 22-Jul-2012.) (Proof modification is discouraged.) (New usage is discouraged.) |
⊢ (𝐴 ∈ 𝑉 → ⦋𝐴 / 𝑥⦌𝐵 = 𝐵) | ||
Theorem | csbgfi 3913 | Substitution for a variable not free in a class does not affect it, in inference form. (Contributed by Giovanni Mascellani, 4-Jun-2019.) |
⊢ 𝐴 ∈ V & ⊢ Ⅎ𝑥𝐵 ⇒ ⊢ ⦋𝐴 / 𝑥⦌𝐵 = 𝐵 | ||
Theorem | csbconstgi 3914* | The proper substitution of a class for a variable in another variable does not modify it, in inference form. (Contributed by Giovanni Mascellani, 30-May-2019.) |
⊢ 𝐴 ∈ V ⇒ ⊢ ⦋𝐴 / 𝑥⦌𝑦 = 𝑦 | ||
Theorem | nfcsb1d 3915 | Bound-variable hypothesis builder for substitution into a class. (Contributed by Mario Carneiro, 12-Oct-2016.) |
⊢ (𝜑 → Ⅎ𝑥𝐴) ⇒ ⊢ (𝜑 → Ⅎ𝑥⦋𝐴 / 𝑥⦌𝐵) | ||
Theorem | nfcsb1 3916 | Bound-variable hypothesis builder for substitution into a class. (Contributed by Mario Carneiro, 12-Oct-2016.) |
⊢ Ⅎ𝑥𝐴 ⇒ ⊢ Ⅎ𝑥⦋𝐴 / 𝑥⦌𝐵 | ||
Theorem | nfcsb1v 3917* | Bound-variable hypothesis builder for substitution into a class. (Contributed by NM, 17-Aug-2006.) (Revised by Mario Carneiro, 12-Oct-2016.) |
⊢ Ⅎ𝑥⦋𝐴 / 𝑥⦌𝐵 | ||
Theorem | nfcsbd 3918 | Deduction version of nfcsb 3920. Usage of this theorem is discouraged because it depends on ax-13 2369. (Contributed by NM, 21-Nov-2005.) (Revised by Mario Carneiro, 12-Oct-2016.) (New usage is discouraged.) |
⊢ Ⅎ𝑦𝜑 & ⊢ (𝜑 → Ⅎ𝑥𝐴) & ⊢ (𝜑 → Ⅎ𝑥𝐵) ⇒ ⊢ (𝜑 → Ⅎ𝑥⦋𝐴 / 𝑦⦌𝐵) | ||
Theorem | nfcsbw 3919* | Bound-variable hypothesis builder for substitution into a class. Version of nfcsb 3920 with a disjoint variable condition, which does not require ax-13 2369. (Contributed by Mario Carneiro, 12-Oct-2016.) Avoid ax-13 2369. (Revised by Gino Giotto, 10-Jan-2024.) |
⊢ Ⅎ𝑥𝐴 & ⊢ Ⅎ𝑥𝐵 ⇒ ⊢ Ⅎ𝑥⦋𝐴 / 𝑦⦌𝐵 | ||
Theorem | nfcsb 3920 | Bound-variable hypothesis builder for substitution into a class. Usage of this theorem is discouraged because it depends on ax-13 2369. Use the weaker nfcsbw 3919 when possible. (Contributed by Mario Carneiro, 12-Oct-2016.) (New usage is discouraged.) |
⊢ Ⅎ𝑥𝐴 & ⊢ Ⅎ𝑥𝐵 ⇒ ⊢ Ⅎ𝑥⦋𝐴 / 𝑦⦌𝐵 | ||
Theorem | csbhypf 3921* | Introduce an explicit substitution into an implicit substitution hypothesis. See sbhypf 3537 for class substitution version. (Contributed by NM, 19-Dec-2008.) |
⊢ Ⅎ𝑥𝐴 & ⊢ Ⅎ𝑥𝐶 & ⊢ (𝑥 = 𝐴 → 𝐵 = 𝐶) ⇒ ⊢ (𝑦 = 𝐴 → ⦋𝑦 / 𝑥⦌𝐵 = 𝐶) | ||
Theorem | csbiebt 3922* | Conversion of implicit substitution to explicit substitution into a class. (Closed theorem version of csbiegf 3926.) (Contributed by NM, 11-Nov-2005.) |
⊢ ((𝐴 ∈ 𝑉 ∧ Ⅎ𝑥𝐶) → (∀𝑥(𝑥 = 𝐴 → 𝐵 = 𝐶) ↔ ⦋𝐴 / 𝑥⦌𝐵 = 𝐶)) | ||
Theorem | csbiedf 3923* | Conversion of implicit substitution to explicit substitution into a class. (Contributed by Mario Carneiro, 13-Oct-2016.) |
⊢ Ⅎ𝑥𝜑 & ⊢ (𝜑 → Ⅎ𝑥𝐶) & ⊢ (𝜑 → 𝐴 ∈ 𝑉) & ⊢ ((𝜑 ∧ 𝑥 = 𝐴) → 𝐵 = 𝐶) ⇒ ⊢ (𝜑 → ⦋𝐴 / 𝑥⦌𝐵 = 𝐶) | ||
Theorem | csbieb 3924* | Bidirectional conversion between an implicit class substitution hypothesis 𝑥 = 𝐴 → 𝐵 = 𝐶 and its explicit substitution equivalent. (Contributed by NM, 2-Mar-2008.) |
⊢ 𝐴 ∈ V & ⊢ Ⅎ𝑥𝐶 ⇒ ⊢ (∀𝑥(𝑥 = 𝐴 → 𝐵 = 𝐶) ↔ ⦋𝐴 / 𝑥⦌𝐵 = 𝐶) | ||
Theorem | csbiebg 3925* | Bidirectional conversion between an implicit class substitution hypothesis 𝑥 = 𝐴 → 𝐵 = 𝐶 and its explicit substitution equivalent. (Contributed by NM, 24-Mar-2013.) (Revised by Mario Carneiro, 11-Dec-2016.) |
⊢ Ⅎ𝑥𝐶 ⇒ ⊢ (𝐴 ∈ 𝑉 → (∀𝑥(𝑥 = 𝐴 → 𝐵 = 𝐶) ↔ ⦋𝐴 / 𝑥⦌𝐵 = 𝐶)) | ||
Theorem | csbiegf 3926* | Conversion of implicit substitution to explicit substitution into a class. (Contributed by NM, 11-Nov-2005.) (Revised by Mario Carneiro, 13-Oct-2016.) |
⊢ (𝐴 ∈ 𝑉 → Ⅎ𝑥𝐶) & ⊢ (𝑥 = 𝐴 → 𝐵 = 𝐶) ⇒ ⊢ (𝐴 ∈ 𝑉 → ⦋𝐴 / 𝑥⦌𝐵 = 𝐶) | ||
Theorem | csbief 3927* | Conversion of implicit substitution to explicit substitution into a class. (Contributed by NM, 26-Nov-2005.) (Revised by Mario Carneiro, 13-Oct-2016.) |
⊢ 𝐴 ∈ V & ⊢ Ⅎ𝑥𝐶 & ⊢ (𝑥 = 𝐴 → 𝐵 = 𝐶) ⇒ ⊢ ⦋𝐴 / 𝑥⦌𝐵 = 𝐶 | ||
Theorem | csbie 3928* | Conversion of implicit substitution to explicit substitution into a class. (Contributed by AV, 2-Dec-2019.) Reduce axiom usage. (Revised by Gino Giotto, 15-Oct-2024.) |
⊢ 𝐴 ∈ V & ⊢ (𝑥 = 𝐴 → 𝐵 = 𝐶) ⇒ ⊢ ⦋𝐴 / 𝑥⦌𝐵 = 𝐶 | ||
Theorem | csbieOLD 3929* | Obsolete version of csbie 3928 as of 15-Oct-2024. (Contributed by AV, 2-Dec-2019.) (Proof modification is discouraged.) (New usage is discouraged.) |
⊢ 𝐴 ∈ V & ⊢ (𝑥 = 𝐴 → 𝐵 = 𝐶) ⇒ ⊢ ⦋𝐴 / 𝑥⦌𝐵 = 𝐶 | ||
Theorem | csbied 3930* | Conversion of implicit substitution to explicit substitution into a class. (Contributed by Mario Carneiro, 2-Dec-2014.) (Revised by Mario Carneiro, 13-Oct-2016.) Reduce axiom usage. (Revised by Gino Giotto, 15-Oct-2024.) |
⊢ (𝜑 → 𝐴 ∈ 𝑉) & ⊢ ((𝜑 ∧ 𝑥 = 𝐴) → 𝐵 = 𝐶) ⇒ ⊢ (𝜑 → ⦋𝐴 / 𝑥⦌𝐵 = 𝐶) | ||
Theorem | csbiedOLD 3931* | Obsolete version of csbied 3930 as of 15-Oct-2024. (Contributed by Mario Carneiro, 2-Dec-2014.) (Revised by Mario Carneiro, 13-Oct-2016.) (Proof modification is discouraged.) (New usage is discouraged.) |
⊢ (𝜑 → 𝐴 ∈ 𝑉) & ⊢ ((𝜑 ∧ 𝑥 = 𝐴) → 𝐵 = 𝐶) ⇒ ⊢ (𝜑 → ⦋𝐴 / 𝑥⦌𝐵 = 𝐶) | ||
Theorem | csbied2 3932* | Conversion of implicit substitution to explicit class substitution, deduction form. (Contributed by Mario Carneiro, 2-Jan-2017.) |
⊢ (𝜑 → 𝐴 ∈ 𝑉) & ⊢ (𝜑 → 𝐴 = 𝐵) & ⊢ ((𝜑 ∧ 𝑥 = 𝐵) → 𝐶 = 𝐷) ⇒ ⊢ (𝜑 → ⦋𝐴 / 𝑥⦌𝐶 = 𝐷) | ||
Theorem | csbie2t 3933* | Conversion of implicit substitution to explicit substitution into a class (closed form of csbie2 3934). (Contributed by NM, 3-Sep-2007.) (Revised by Mario Carneiro, 13-Oct-2016.) |
⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈ V ⇒ ⊢ (∀𝑥∀𝑦((𝑥 = 𝐴 ∧ 𝑦 = 𝐵) → 𝐶 = 𝐷) → ⦋𝐴 / 𝑥⦌⦋𝐵 / 𝑦⦌𝐶 = 𝐷) | ||
Theorem | csbie2 3934* | Conversion of implicit substitution to explicit substitution into a class. (Contributed by NM, 27-Aug-2007.) |
⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈ V & ⊢ ((𝑥 = 𝐴 ∧ 𝑦 = 𝐵) → 𝐶 = 𝐷) ⇒ ⊢ ⦋𝐴 / 𝑥⦌⦋𝐵 / 𝑦⦌𝐶 = 𝐷 | ||
Theorem | csbie2g 3935* | Conversion of implicit substitution to explicit class substitution. This version of csbie 3928 avoids a disjointness condition on 𝑥, 𝐴 and 𝑥, 𝐷 by substituting twice. (Contributed by Mario Carneiro, 11-Nov-2016.) |
⊢ (𝑥 = 𝑦 → 𝐵 = 𝐶) & ⊢ (𝑦 = 𝐴 → 𝐶 = 𝐷) ⇒ ⊢ (𝐴 ∈ 𝑉 → ⦋𝐴 / 𝑥⦌𝐵 = 𝐷) | ||
Theorem | cbvrabcsfw 3936* | Version of cbvrabcsf 3940 with a disjoint variable condition, which does not require ax-13 2369. (Contributed by Andrew Salmon, 13-Jul-2011.) (Revised by Gino Giotto, 26-Jan-2024.) |
⊢ Ⅎ𝑦𝐴 & ⊢ Ⅎ𝑥𝐵 & ⊢ Ⅎ𝑦𝜑 & ⊢ Ⅎ𝑥𝜓 & ⊢ (𝑥 = 𝑦 → 𝐴 = 𝐵) & ⊢ (𝑥 = 𝑦 → (𝜑 ↔ 𝜓)) ⇒ ⊢ {𝑥 ∈ 𝐴 ∣ 𝜑} = {𝑦 ∈ 𝐵 ∣ 𝜓} | ||
Theorem | cbvralcsf 3937 | A more general version of cbvralf 3354 that doesn't require 𝐴 and 𝐵 to be distinct from 𝑥 or 𝑦. Changes bound variables using implicit substitution. Usage of this theorem is discouraged because it depends on ax-13 2369. (Contributed by Andrew Salmon, 13-Jul-2011.) (New usage is discouraged.) |
⊢ Ⅎ𝑦𝐴 & ⊢ Ⅎ𝑥𝐵 & ⊢ Ⅎ𝑦𝜑 & ⊢ Ⅎ𝑥𝜓 & ⊢ (𝑥 = 𝑦 → 𝐴 = 𝐵) & ⊢ (𝑥 = 𝑦 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∀𝑥 ∈ 𝐴 𝜑 ↔ ∀𝑦 ∈ 𝐵 𝜓) | ||
Theorem | cbvrexcsf 3938 | A more general version of cbvrexf 3355 that has no distinct variable restrictions. Changes bound variables using implicit substitution. Usage of this theorem is discouraged because it depends on ax-13 2369. (Contributed by Andrew Salmon, 13-Jul-2011.) (Proof shortened by Mario Carneiro, 7-Dec-2014.) (New usage is discouraged.) |
⊢ Ⅎ𝑦𝐴 & ⊢ Ⅎ𝑥𝐵 & ⊢ Ⅎ𝑦𝜑 & ⊢ Ⅎ𝑥𝜓 & ⊢ (𝑥 = 𝑦 → 𝐴 = 𝐵) & ⊢ (𝑥 = 𝑦 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∃𝑥 ∈ 𝐴 𝜑 ↔ ∃𝑦 ∈ 𝐵 𝜓) | ||
Theorem | cbvreucsf 3939 | A more general version of cbvreuv 3425 that has no distinct variable restrictions. Changes bound variables using implicit substitution. Usage of this theorem is discouraged because it depends on ax-13 2369. (Contributed by Andrew Salmon, 13-Jul-2011.) (New usage is discouraged.) |
⊢ Ⅎ𝑦𝐴 & ⊢ Ⅎ𝑥𝐵 & ⊢ Ⅎ𝑦𝜑 & ⊢ Ⅎ𝑥𝜓 & ⊢ (𝑥 = 𝑦 → 𝐴 = 𝐵) & ⊢ (𝑥 = 𝑦 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∃!𝑥 ∈ 𝐴 𝜑 ↔ ∃!𝑦 ∈ 𝐵 𝜓) | ||
Theorem | cbvrabcsf 3940 | A more general version of cbvrab 3471 with no distinct variable restrictions. Usage of this theorem is discouraged because it depends on ax-13 2369. (Contributed by Andrew Salmon, 13-Jul-2011.) (New usage is discouraged.) |
⊢ Ⅎ𝑦𝐴 & ⊢ Ⅎ𝑥𝐵 & ⊢ Ⅎ𝑦𝜑 & ⊢ Ⅎ𝑥𝜓 & ⊢ (𝑥 = 𝑦 → 𝐴 = 𝐵) & ⊢ (𝑥 = 𝑦 → (𝜑 ↔ 𝜓)) ⇒ ⊢ {𝑥 ∈ 𝐴 ∣ 𝜑} = {𝑦 ∈ 𝐵 ∣ 𝜓} | ||
Theorem | cbvralv2 3941* | Rule used to change the bound variable in a restricted universal quantifier with implicit substitution which also changes the quantifier domain. Usage of this theorem is discouraged because it depends on ax-13 2369. (Contributed by David Moews, 1-May-2017.) (New usage is discouraged.) |
⊢ (𝑥 = 𝑦 → (𝜓 ↔ 𝜒)) & ⊢ (𝑥 = 𝑦 → 𝐴 = 𝐵) ⇒ ⊢ (∀𝑥 ∈ 𝐴 𝜓 ↔ ∀𝑦 ∈ 𝐵 𝜒) | ||
Theorem | cbvrexv2 3942* | Rule used to change the bound variable in a restricted existential quantifier with implicit substitution which also changes the quantifier domain. Usage of this theorem is discouraged because it depends on ax-13 2369. (Contributed by David Moews, 1-May-2017.) (New usage is discouraged.) |
⊢ (𝑥 = 𝑦 → (𝜓 ↔ 𝜒)) & ⊢ (𝑥 = 𝑦 → 𝐴 = 𝐵) ⇒ ⊢ (∃𝑥 ∈ 𝐴 𝜓 ↔ ∃𝑦 ∈ 𝐵 𝜒) | ||
Theorem | rspc2vd 3943* | Deduction version of 2-variable restricted specialization, using implicit substitution. Notice that the class 𝐷 for the second set variable 𝑦 may depend on the first set variable 𝑥. (Contributed by AV, 29-Mar-2021.) |
⊢ (𝑥 = 𝐴 → (𝜃 ↔ 𝜒)) & ⊢ (𝑦 = 𝐵 → (𝜒 ↔ 𝜓)) & ⊢ (𝜑 → 𝐴 ∈ 𝐶) & ⊢ ((𝜑 ∧ 𝑥 = 𝐴) → 𝐷 = 𝐸) & ⊢ (𝜑 → 𝐵 ∈ 𝐸) ⇒ ⊢ (𝜑 → (∀𝑥 ∈ 𝐶 ∀𝑦 ∈ 𝐷 𝜃 → 𝜓)) | ||
Syntax | cdif 3944 | Extend class notation to include class difference (read: "𝐴 minus 𝐵"). |
class (𝐴 ∖ 𝐵) | ||
Syntax | cun 3945 | Extend class notation to include union of two classes (read: "𝐴 union 𝐵"). |
class (𝐴 ∪ 𝐵) | ||
Syntax | cin 3946 | Extend class notation to include the intersection of two classes (read: "𝐴 intersect 𝐵"). |
class (𝐴 ∩ 𝐵) | ||
Syntax | wss 3947 | Extend wff notation to include the subclass relation. This is read "𝐴 is a subclass of 𝐵 " or "𝐵 includes 𝐴". When 𝐴 exists as a set, it is also read "𝐴 is a subset of 𝐵". |
wff 𝐴 ⊆ 𝐵 | ||
Syntax | wpss 3948 | Extend wff notation with proper subclass relation. |
wff 𝐴 ⊊ 𝐵 | ||
Theorem | difjust 3949* | Soundness justification theorem for df-dif 3950. (Contributed by Rodolfo Medina, 27-Apr-2010.) (Proof shortened by Andrew Salmon, 9-Jul-2011.) |
⊢ {𝑥 ∣ (𝑥 ∈ 𝐴 ∧ ¬ 𝑥 ∈ 𝐵)} = {𝑦 ∣ (𝑦 ∈ 𝐴 ∧ ¬ 𝑦 ∈ 𝐵)} | ||
Definition | df-dif 3950* | Define class difference, also called relative complement. Definition 5.12 of [TakeutiZaring] p. 20. For example, ({1, 3} ∖ {1, 8}) = {3} (ex-dif 29943). Contrast this operation with union (𝐴 ∪ 𝐵) (df-un 3952) and intersection (𝐴 ∩ 𝐵) (df-in 3954). Several notations are used in the literature; we chose the ∖ convention used in Definition 5.3 of [Eisenberg] p. 67 instead of the more common minus sign to reserve the latter for later use in, e.g., arithmetic. We will use the terminology "𝐴 excludes 𝐵 " to mean 𝐴 ∖ 𝐵. We will use "𝐵 is removed from 𝐴 " to mean 𝐴 ∖ {𝐵} i.e. the removal of an element or equivalently the exclusion of a singleton. (Contributed by NM, 29-Apr-1994.) |
⊢ (𝐴 ∖ 𝐵) = {𝑥 ∣ (𝑥 ∈ 𝐴 ∧ ¬ 𝑥 ∈ 𝐵)} | ||
Theorem | unjust 3951* | Soundness justification theorem for df-un 3952. (Contributed by Rodolfo Medina, 28-Apr-2010.) (Proof shortened by Andrew Salmon, 9-Jul-2011.) |
⊢ {𝑥 ∣ (𝑥 ∈ 𝐴 ∨ 𝑥 ∈ 𝐵)} = {𝑦 ∣ (𝑦 ∈ 𝐴 ∨ 𝑦 ∈ 𝐵)} | ||
Definition | df-un 3952* | Define the union of two classes. Definition 5.6 of [TakeutiZaring] p. 16. For example, ({1, 3} ∪ {1, 8}) = {1, 3, 8} (ex-un 29944). Contrast this operation with difference (𝐴 ∖ 𝐵) (df-dif 3950) and intersection (𝐴 ∩ 𝐵) (df-in 3954). For an alternate definition in terms of class difference, requiring no dummy variables, see dfun2 4258. For union defined in terms of intersection, see dfun3 4264. (Contributed by NM, 23-Aug-1993.) |
⊢ (𝐴 ∪ 𝐵) = {𝑥 ∣ (𝑥 ∈ 𝐴 ∨ 𝑥 ∈ 𝐵)} | ||
Theorem | injust 3953* | Soundness justification theorem for df-in 3954. (Contributed by Rodolfo Medina, 28-Apr-2010.) (Proof shortened by Andrew Salmon, 9-Jul-2011.) |
⊢ {𝑥 ∣ (𝑥 ∈ 𝐴 ∧ 𝑥 ∈ 𝐵)} = {𝑦 ∣ (𝑦 ∈ 𝐴 ∧ 𝑦 ∈ 𝐵)} | ||
Definition | df-in 3954* | Define the intersection of two classes. Definition 5.6 of [TakeutiZaring] p. 16. For example, ({1, 3} ∩ {1, 8}) = {1} (ex-in 29945). Contrast this operation with union (𝐴 ∪ 𝐵) (df-un 3952) and difference (𝐴 ∖ 𝐵) (df-dif 3950). For alternate definitions in terms of class difference, requiring no dummy variables, see dfin2 4259 and dfin4 4266. For intersection defined in terms of union, see dfin3 4265. (Contributed by NM, 29-Apr-1994.) |
⊢ (𝐴 ∩ 𝐵) = {𝑥 ∣ (𝑥 ∈ 𝐴 ∧ 𝑥 ∈ 𝐵)} | ||
Theorem | dfin5 3955* | Alternate definition for the intersection of two classes. (Contributed by NM, 6-Jul-2005.) |
⊢ (𝐴 ∩ 𝐵) = {𝑥 ∈ 𝐴 ∣ 𝑥 ∈ 𝐵} | ||
Theorem | dfdif2 3956* | Alternate definition of class difference. (Contributed by NM, 25-Mar-2004.) |
⊢ (𝐴 ∖ 𝐵) = {𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝐵} | ||
Theorem | eldif 3957 | Expansion of membership in a class difference. (Contributed by NM, 29-Apr-1994.) |
⊢ (𝐴 ∈ (𝐵 ∖ 𝐶) ↔ (𝐴 ∈ 𝐵 ∧ ¬ 𝐴 ∈ 𝐶)) | ||
Theorem | eldifd 3958 | If a class is in one class and not another, it is also in their difference. One-way deduction form of eldif 3957. (Contributed by David Moews, 1-May-2017.) |
⊢ (𝜑 → 𝐴 ∈ 𝐵) & ⊢ (𝜑 → ¬ 𝐴 ∈ 𝐶) ⇒ ⊢ (𝜑 → 𝐴 ∈ (𝐵 ∖ 𝐶)) | ||
Theorem | eldifad 3959 | If a class is in the difference of two classes, it is also in the minuend. One-way deduction form of eldif 3957. (Contributed by David Moews, 1-May-2017.) |
⊢ (𝜑 → 𝐴 ∈ (𝐵 ∖ 𝐶)) ⇒ ⊢ (𝜑 → 𝐴 ∈ 𝐵) | ||
Theorem | eldifbd 3960 | If a class is in the difference of two classes, it is not in the subtrahend. One-way deduction form of eldif 3957. (Contributed by David Moews, 1-May-2017.) |
⊢ (𝜑 → 𝐴 ∈ (𝐵 ∖ 𝐶)) ⇒ ⊢ (𝜑 → ¬ 𝐴 ∈ 𝐶) | ||
Theorem | elneeldif 3961 | The elements of a set difference and the minuend are not equal. (Contributed by AV, 21-Oct-2023.) |
⊢ ((𝑋 ∈ 𝐴 ∧ 𝑌 ∈ (𝐵 ∖ 𝐴)) → 𝑋 ≠ 𝑌) | ||
Theorem | velcomp 3962 | Characterization of setvar elements of the complement of a class. (Contributed by Andrew Salmon, 15-Jul-2011.) |
⊢ (𝑥 ∈ (V ∖ 𝐴) ↔ ¬ 𝑥 ∈ 𝐴) | ||
Theorem | elin 3963 | Expansion of membership in an intersection of two classes. Theorem 12 of [Suppes] p. 25. (Contributed by NM, 29-Apr-1994.) |
⊢ (𝐴 ∈ (𝐵 ∩ 𝐶) ↔ (𝐴 ∈ 𝐵 ∧ 𝐴 ∈ 𝐶)) | ||
Definition | df-ss 3964 |
Define the subclass relationship. Exercise 9 of [TakeutiZaring] p. 18.
For example, {1, 2} ⊆ {1, 2, 3} (ex-ss 29947). Note that
𝐴
⊆ 𝐴 (proved in
ssid 4003). Contrast this relationship with the
relationship 𝐴 ⊊ 𝐵 (as will be defined in df-pss 3966). For a more
traditional definition, but requiring a dummy variable, see dfss2 3967.
Other possible definitions are given by dfss3 3969, dfss4 4257, sspss 4098,
ssequn1 4179, ssequn2 4182, sseqin2 4214, and ssdif0 4362.
We prefer the label "ss" ("subset") for ⊆, despite the fact that it applies to classes. It is much more common to refer to this as the subset relation than subclass, especially since most of the time the arguments are in fact sets (and for pragmatic reasons we don't want to need to use different operations for sets). The way set.mm is set up, many things are technically classes despite morally (and provably) being sets, like 1 (cf. df-1 11120 and 1ex 11214) or ℝ ( cf. df-r 11122 and reex 11203). This has to do with the fact that there are no "set expressions": classes are expressions but there are only set variables in set.mm (cf. https://us.metamath.org/downloads/grammar-ambiguity.txt 11203). This is why we use ⊆ both for subclass relations and for subset relations and call it "subset". (Contributed by NM, 27-Apr-1994.) |
⊢ (𝐴 ⊆ 𝐵 ↔ (𝐴 ∩ 𝐵) = 𝐴) | ||
Theorem | dfss 3965 | Variant of subclass definition df-ss 3964. (Contributed by NM, 21-Jun-1993.) |
⊢ (𝐴 ⊆ 𝐵 ↔ 𝐴 = (𝐴 ∩ 𝐵)) | ||
Definition | df-pss 3966 | Define proper subclass (or strict subclass) relationship between two classes. Definition 5.9 of [TakeutiZaring] p. 17. For example, {1, 2} ⊊ {1, 2, 3} (ex-pss 29948). Note that ¬ 𝐴 ⊊ 𝐴 (proved in pssirr 4099). Contrast this relationship with the relationship 𝐴 ⊆ 𝐵 (as defined in df-ss 3964). Other possible definitions are given by dfpss2 4084 and dfpss3 4085. (Contributed by NM, 7-Feb-1996.) |
⊢ (𝐴 ⊊ 𝐵 ↔ (𝐴 ⊆ 𝐵 ∧ 𝐴 ≠ 𝐵)) | ||
Theorem | dfss2 3967* | Alternate definition of the subclass relationship between two classes. Definition 5.9 of [TakeutiZaring] p. 17. (Contributed by NM, 8-Jan-2002.) Avoid ax-10 2135, ax-11 2152, ax-12 2169. (Revised by SN, 16-May-2024.) |
⊢ (𝐴 ⊆ 𝐵 ↔ ∀𝑥(𝑥 ∈ 𝐴 → 𝑥 ∈ 𝐵)) | ||
Theorem | dfss2OLD 3968* | Obsolete version of dfss2 3967 as of 16-May-2024. (Contributed by NM, 8-Jan-2002.) (Proof modification is discouraged.) (New usage is discouraged.) |
⊢ (𝐴 ⊆ 𝐵 ↔ ∀𝑥(𝑥 ∈ 𝐴 → 𝑥 ∈ 𝐵)) | ||
Theorem | dfss3 3969* | Alternate definition of subclass relationship. (Contributed by NM, 14-Oct-1999.) |
⊢ (𝐴 ⊆ 𝐵 ↔ ∀𝑥 ∈ 𝐴 𝑥 ∈ 𝐵) | ||
Theorem | dfss6 3970* | Alternate definition of subclass relationship. (Contributed by RP, 16-Apr-2020.) |
⊢ (𝐴 ⊆ 𝐵 ↔ ¬ ∃𝑥(𝑥 ∈ 𝐴 ∧ ¬ 𝑥 ∈ 𝐵)) | ||
Theorem | dfss2f 3971 | Equivalence for subclass relation, using bound-variable hypotheses instead of distinct variable conditions. (Contributed by NM, 3-Jul-1994.) (Revised by Andrew Salmon, 27-Aug-2011.) Avoid ax-13 2369. (Revised by Gino Giotto, 19-May-2023.) |
⊢ Ⅎ𝑥𝐴 & ⊢ Ⅎ𝑥𝐵 ⇒ ⊢ (𝐴 ⊆ 𝐵 ↔ ∀𝑥(𝑥 ∈ 𝐴 → 𝑥 ∈ 𝐵)) | ||
Theorem | dfss3f 3972 | Equivalence for subclass relation, using bound-variable hypotheses instead of distinct variable conditions. (Contributed by NM, 20-Mar-2004.) |
⊢ Ⅎ𝑥𝐴 & ⊢ Ⅎ𝑥𝐵 ⇒ ⊢ (𝐴 ⊆ 𝐵 ↔ ∀𝑥 ∈ 𝐴 𝑥 ∈ 𝐵) | ||
Theorem | nfss 3973 | If 𝑥 is not free in 𝐴 and 𝐵, it is not free in 𝐴 ⊆ 𝐵. (Contributed by NM, 27-Dec-1996.) |
⊢ Ⅎ𝑥𝐴 & ⊢ Ⅎ𝑥𝐵 ⇒ ⊢ Ⅎ𝑥 𝐴 ⊆ 𝐵 | ||
Theorem | ssel 3974 | Membership relationships follow from a subclass relationship. (Contributed by NM, 5-Aug-1993.) Avoid ax-12 2169. (Revised by SN, 27-May-2024.) |
⊢ (𝐴 ⊆ 𝐵 → (𝐶 ∈ 𝐴 → 𝐶 ∈ 𝐵)) | ||
Theorem | sselOLD 3975 | Obsolete version of ssel 3974 as of 27-May-2024. (Contributed by NM, 5-Aug-1993.) (Proof modification is discouraged.) (New usage is discouraged.) |
⊢ (𝐴 ⊆ 𝐵 → (𝐶 ∈ 𝐴 → 𝐶 ∈ 𝐵)) | ||
Theorem | ssel2 3976 | Membership relationships follow from a subclass relationship. (Contributed by NM, 7-Jun-2004.) |
⊢ ((𝐴 ⊆ 𝐵 ∧ 𝐶 ∈ 𝐴) → 𝐶 ∈ 𝐵) | ||
Theorem | sseli 3977 | Membership implication from subclass relationship. (Contributed by NM, 5-Aug-1993.) |
⊢ 𝐴 ⊆ 𝐵 ⇒ ⊢ (𝐶 ∈ 𝐴 → 𝐶 ∈ 𝐵) | ||
Theorem | sselii 3978 | Membership inference from subclass relationship. (Contributed by NM, 31-May-1999.) |
⊢ 𝐴 ⊆ 𝐵 & ⊢ 𝐶 ∈ 𝐴 ⇒ ⊢ 𝐶 ∈ 𝐵 | ||
Theorem | sselid 3979 | Membership inference from subclass relationship. (Contributed by NM, 25-Jun-2014.) |
⊢ 𝐴 ⊆ 𝐵 & ⊢ (𝜑 → 𝐶 ∈ 𝐴) ⇒ ⊢ (𝜑 → 𝐶 ∈ 𝐵) | ||
Theorem | sseld 3980 | Membership deduction from subclass relationship. (Contributed by NM, 15-Nov-1995.) |
⊢ (𝜑 → 𝐴 ⊆ 𝐵) ⇒ ⊢ (𝜑 → (𝐶 ∈ 𝐴 → 𝐶 ∈ 𝐵)) | ||
Theorem | sselda 3981 | Membership deduction from subclass relationship. (Contributed by NM, 26-Jun-2014.) |
⊢ (𝜑 → 𝐴 ⊆ 𝐵) ⇒ ⊢ ((𝜑 ∧ 𝐶 ∈ 𝐴) → 𝐶 ∈ 𝐵) | ||
Theorem | sseldd 3982 | Membership inference from subclass relationship. (Contributed by NM, 14-Dec-2004.) |
⊢ (𝜑 → 𝐴 ⊆ 𝐵) & ⊢ (𝜑 → 𝐶 ∈ 𝐴) ⇒ ⊢ (𝜑 → 𝐶 ∈ 𝐵) | ||
Theorem | ssneld 3983 | If a class is not in another class, it is also not in a subclass of that class. Deduction form. (Contributed by David Moews, 1-May-2017.) |
⊢ (𝜑 → 𝐴 ⊆ 𝐵) ⇒ ⊢ (𝜑 → (¬ 𝐶 ∈ 𝐵 → ¬ 𝐶 ∈ 𝐴)) | ||
Theorem | ssneldd 3984 | If an element is not in a class, it is also not in a subclass of that class. Deduction form. (Contributed by David Moews, 1-May-2017.) |
⊢ (𝜑 → 𝐴 ⊆ 𝐵) & ⊢ (𝜑 → ¬ 𝐶 ∈ 𝐵) ⇒ ⊢ (𝜑 → ¬ 𝐶 ∈ 𝐴) | ||
Theorem | ssriv 3985* | Inference based on subclass definition. (Contributed by NM, 21-Jun-1993.) |
⊢ (𝑥 ∈ 𝐴 → 𝑥 ∈ 𝐵) ⇒ ⊢ 𝐴 ⊆ 𝐵 | ||
Theorem | ssrd 3986 | Deduction based on subclass definition. (Contributed by Thierry Arnoux, 8-Mar-2017.) |
⊢ Ⅎ𝑥𝜑 & ⊢ Ⅎ𝑥𝐴 & ⊢ Ⅎ𝑥𝐵 & ⊢ (𝜑 → (𝑥 ∈ 𝐴 → 𝑥 ∈ 𝐵)) ⇒ ⊢ (𝜑 → 𝐴 ⊆ 𝐵) | ||
Theorem | ssrdv 3987* | Deduction based on subclass definition. (Contributed by NM, 15-Nov-1995.) |
⊢ (𝜑 → (𝑥 ∈ 𝐴 → 𝑥 ∈ 𝐵)) ⇒ ⊢ (𝜑 → 𝐴 ⊆ 𝐵) | ||
Theorem | sstr2 3988 | Transitivity of subclass relationship. Exercise 5 of [TakeutiZaring] p. 17. (Contributed by NM, 24-Jun-1993.) (Proof shortened by Andrew Salmon, 14-Jun-2011.) |
⊢ (𝐴 ⊆ 𝐵 → (𝐵 ⊆ 𝐶 → 𝐴 ⊆ 𝐶)) | ||
Theorem | sstr 3989 | Transitivity of subclass relationship. Theorem 6 of [Suppes] p. 23. (Contributed by NM, 5-Sep-2003.) |
⊢ ((𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐶) → 𝐴 ⊆ 𝐶) | ||
Theorem | sstri 3990 | Subclass transitivity inference. (Contributed by NM, 5-May-2000.) |
⊢ 𝐴 ⊆ 𝐵 & ⊢ 𝐵 ⊆ 𝐶 ⇒ ⊢ 𝐴 ⊆ 𝐶 | ||
Theorem | sstrd 3991 | Subclass transitivity deduction. (Contributed by NM, 2-Jun-2004.) |
⊢ (𝜑 → 𝐴 ⊆ 𝐵) & ⊢ (𝜑 → 𝐵 ⊆ 𝐶) ⇒ ⊢ (𝜑 → 𝐴 ⊆ 𝐶) | ||
Theorem | sstrid 3992 | Subclass transitivity deduction. (Contributed by NM, 6-Feb-2014.) |
⊢ 𝐴 ⊆ 𝐵 & ⊢ (𝜑 → 𝐵 ⊆ 𝐶) ⇒ ⊢ (𝜑 → 𝐴 ⊆ 𝐶) | ||
Theorem | sstrdi 3993 | Subclass transitivity deduction. (Contributed by Jonathan Ben-Naim, 3-Jun-2011.) |
⊢ (𝜑 → 𝐴 ⊆ 𝐵) & ⊢ 𝐵 ⊆ 𝐶 ⇒ ⊢ (𝜑 → 𝐴 ⊆ 𝐶) | ||
Theorem | sylan9ss 3994 | A subclass transitivity deduction. (Contributed by NM, 27-Sep-2004.) (Proof shortened by Andrew Salmon, 14-Jun-2011.) |
⊢ (𝜑 → 𝐴 ⊆ 𝐵) & ⊢ (𝜓 → 𝐵 ⊆ 𝐶) ⇒ ⊢ ((𝜑 ∧ 𝜓) → 𝐴 ⊆ 𝐶) | ||
Theorem | sylan9ssr 3995 | A subclass transitivity deduction. (Contributed by NM, 27-Sep-2004.) |
⊢ (𝜑 → 𝐴 ⊆ 𝐵) & ⊢ (𝜓 → 𝐵 ⊆ 𝐶) ⇒ ⊢ ((𝜓 ∧ 𝜑) → 𝐴 ⊆ 𝐶) | ||
Theorem | eqss 3996 | The subclass relationship is antisymmetric. Compare Theorem 4 of [Suppes] p. 22. (Contributed by NM, 21-May-1993.) |
⊢ (𝐴 = 𝐵 ↔ (𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐴)) | ||
Theorem | eqssi 3997 | Infer equality from two subclass relationships. Compare Theorem 4 of [Suppes] p. 22. (Contributed by NM, 9-Sep-1993.) |
⊢ 𝐴 ⊆ 𝐵 & ⊢ 𝐵 ⊆ 𝐴 ⇒ ⊢ 𝐴 = 𝐵 | ||
Theorem | eqssd 3998 | Equality deduction from two subclass relationships. Compare Theorem 4 of [Suppes] p. 22. (Contributed by NM, 27-Jun-2004.) |
⊢ (𝜑 → 𝐴 ⊆ 𝐵) & ⊢ (𝜑 → 𝐵 ⊆ 𝐴) ⇒ ⊢ (𝜑 → 𝐴 = 𝐵) | ||
Theorem | sssseq 3999 | If a class is a subclass of another class, then the classes are equal if and only if the other class is a subclass of the first class. (Contributed by AV, 23-Dec-2020.) |
⊢ (𝐵 ⊆ 𝐴 → (𝐴 ⊆ 𝐵 ↔ 𝐴 = 𝐵)) | ||
Theorem | eqrd 4000 | Deduce equality of classes from equivalence of membership. (Contributed by Thierry Arnoux, 21-Mar-2017.) (Proof shortened by BJ, 1-Dec-2021.) |
⊢ Ⅎ𝑥𝜑 & ⊢ Ⅎ𝑥𝐴 & ⊢ Ⅎ𝑥𝐵 & ⊢ (𝜑 → (𝑥 ∈ 𝐴 ↔ 𝑥 ∈ 𝐵)) ⇒ ⊢ (𝜑 → 𝐴 = 𝐵) |
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