Theorem inopnd 45908

Description: The intersection of two open sets of a topology is an open set. (Contributed by Glauco Siliprandi, 21-Dec-2024.)

Hypotheses

Ref	Expression
inopnd.1	⊢ (𝜑 → 𝐽 ∈ Top)
inopnd.2	⊢ (𝜑 → 𝐴 ∈ 𝐽)
inopnd.3	⊢ (𝜑 → 𝐵 ∈ 𝐽)

Assertion

Ref	Expression
inopnd	⊢ (𝜑 → (𝐴 ∩ 𝐵) ∈ 𝐽)

Proof of Theorem inopnd

Step	Hyp	Ref	Expression
1		inopnd.1	. 2 ⊢ (𝜑 → 𝐽 ∈ Top)
2		inopnd.2	. 2 ⊢ (𝜑 → 𝐴 ∈ 𝐽)
3		inopnd.3	. 2 ⊢ (𝜑 → 𝐵 ∈ 𝐽)
4		inopn 23093	. 2 ⊢ ((𝐽 ∈ Top ∧ 𝐴 ∈ 𝐽 ∧ 𝐵 ∈ 𝐽) → (𝐴 ∩ 𝐵) ∈ 𝐽)
5	1, 2, 3, 4	syl3anc 1398	1 ⊢ (𝜑 → (𝐴 ∩ 𝐵) ∈ 𝐽)

This proof depends on syntax axioms:   → wi 4   ∈ wcel 2146   ∩ cin 3907  Topctop 23087

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2148  ax-9 2156  ax-ext 2738  ax-sep 5262

This proof depends on definitions:  df-bi 210  df-an 402  df-3an 1105  df-tru 1573  df-ex 1813  df-sb 2100  df-clab 2745  df-cleq 2758  df-clel 2841  df-ral 3083  df-rex 3093  df-rab 3420  df-v 3460  df-in 3915  df-ss 3925  df-pw 4569  df-top 23088

This theorem is used by: (None)