Theorem nfeu1ALT 2650

Description: Alternate proof of nfeu1 2649. This illustrates the systematic way of proving nonfreeness in a defined expression: consider the definiens as a tree whose nodes are its subformulas, and prove by tree-induction nonfreeness of each node, starting from the leaves (generally using nfv 1915 or nf* theorems for previously defined expressions) and up to the root. Here, the definiens is a conjunction of two previously defined expressions, which automatically yields the present proof. (Contributed by BJ, 2-Oct-2022.) (Proof modification is discouraged.) (New usage is discouraged.)

Assertion

Ref	Expression
nfeu1ALT	⊢ Ⅎ𝑥∃!𝑥𝜑

Proof of Theorem nfeu1ALT

Step	Hyp	Ref	Expression
1		df-eu 2629	. 2 ⊢ (∃!𝑥𝜑 ↔ (∃𝑥𝜑 ∧ ∃*𝑥𝜑))
2		nfe1 2151	. . 3 ⊢ Ⅎ𝑥∃𝑥𝜑
3		nfmo1 2616	. . 3 ⊢ Ⅎ𝑥∃*𝑥𝜑
4	2, 3	nfan 1900	. 2 ⊢ Ⅎ𝑥(∃𝑥𝜑 ∧ ∃*𝑥𝜑)
5	1, 4	nfxfr 1854	1 ⊢ Ⅎ𝑥∃!𝑥𝜑

Syntax hints:   ∧ wa 399  ∃wex 1781  Ⅎwnf 1785  ∃*wmo 2596  ∃!weu 2628

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1911  ax-6 1970  ax-7 2015  ax-10 2142  ax-11 2158  ax-12 2175

This theorem depends on definitions:  df-bi 210  df-an 400  df-or 845  df-tru 1541  df-ex 1782  df-nf 1786  df-mo 2598  df-eu 2629

This theorem is referenced by: (None)