Theorem npss 4069

Description: A class is not a proper subclass of another iff it satisfies a one-directional form of eqss 3953. (Contributed by Mario Carneiro, 15-May-2015.)

Assertion

Ref	Expression
npss	⊢ (¬ 𝐴 ⊊ 𝐵 ↔ (𝐴 ⊆ 𝐵 → 𝐴 = 𝐵))

Proof of Theorem npss

Step	Hyp	Ref	Expression
1		pm4.61 410	. . 3 ⊢ (¬ (𝐴 ⊆ 𝐵 → 𝐴 = 𝐵) ↔ (𝐴 ⊆ 𝐵 ∧ ¬ 𝐴 = 𝐵))
2		dfpss2 4043	. . 3 ⊢ (𝐴 ⊊ 𝐵 ↔ (𝐴 ⊆ 𝐵 ∧ ¬ 𝐴 = 𝐵))
3	1, 2	bitr4i 281	. 2 ⊢ (¬ (𝐴 ⊆ 𝐵 → 𝐴 = 𝐵) ↔ 𝐴 ⊊ 𝐵)
4	3	con1bii 359	1 ⊢ (¬ 𝐴 ⊊ 𝐵 ↔ (𝐴 ⊆ 𝐵 → 𝐴 = 𝐵))

This proof depends on syntax axioms:  ¬ wn 3   → wi 4   ↔ wb 209   ∧ wa 401   = wceq 1570   ⊆ wss 3906   ⊊ wpss 3907

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This proof depends on definitions:  df-bi 210  df-an 402  df-ne 2961  df-pss 3926

This theorem is used by:  ttukeylem7  10514  canthp1lem2  10655  pgpfac1lem1  20192  lspsncv0  21322  obslbs  21932  ssmxidl  33823  fvineqsneq  38117