Theorem npss 4090

Description: A class is not a proper subclass of another iff it satisfies a one-directional form of eqss 3985. (Contributed by Mario Carneiro, 15-May-2015.)

Assertion

Ref	Expression
npss	⊢ (¬ 𝐴 ⊊ 𝐵 ↔ (𝐴 ⊆ 𝐵 → 𝐴 = 𝐵))

Proof of Theorem npss

Step	Hyp	Ref	Expression
1		pm4.61 407	. . 3 ⊢ (¬ (𝐴 ⊆ 𝐵 → 𝐴 = 𝐵) ↔ (𝐴 ⊆ 𝐵 ∧ ¬ 𝐴 = 𝐵))
2		dfpss2 4065	. . 3 ⊢ (𝐴 ⊊ 𝐵 ↔ (𝐴 ⊆ 𝐵 ∧ ¬ 𝐴 = 𝐵))
3	1, 2	bitr4i 280	. 2 ⊢ (¬ (𝐴 ⊆ 𝐵 → 𝐴 = 𝐵) ↔ 𝐴 ⊊ 𝐵)
4	3	con1bii 359	1 ⊢ (¬ 𝐴 ⊊ 𝐵 ↔ (𝐴 ⊆ 𝐵 → 𝐴 = 𝐵))

Syntax hints:  ¬ wn 3   → wi 4   ↔ wb 208   ∧ wa 398   = wceq 1536   ⊆ wss 3939   ⊊ wpss 3940

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 209  df-an 399  df-ne 3020  df-pss 3957

This theorem is referenced by:  ttukeylem7  9940  canthp1lem2  10078  pgpfac1lem1  19199  lspsncv0  19921  obslbs  20877  ssmxidl  30983  fvineqsneq  34697