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Mirrors > Home > MPE Home > Th. List > Mathboxes > opnneilem | Structured version Visualization version GIF version |
Description: Lemma factoring out common proof steps of opnneil 46155 and opnneirv 46153. (Contributed by Zhi Wang, 31-Aug-2024.) |
Ref | Expression |
---|---|
opnneilem.1 | ⊢ ((𝜑 ∧ 𝑥 = 𝑦) → (𝜓 ↔ 𝜒)) |
Ref | Expression |
---|---|
opnneilem | ⊢ (𝜑 → (∃𝑥 ∈ 𝐽 (𝑆 ⊆ 𝑥 ∧ 𝜓) ↔ ∃𝑦 ∈ 𝐽 (𝑆 ⊆ 𝑦 ∧ 𝜒))) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | sseq2 3951 | . . . 4 ⊢ (𝑥 = 𝑦 → (𝑆 ⊆ 𝑥 ↔ 𝑆 ⊆ 𝑦)) | |
2 | 1 | adantl 481 | . . 3 ⊢ ((𝜑 ∧ 𝑥 = 𝑦) → (𝑆 ⊆ 𝑥 ↔ 𝑆 ⊆ 𝑦)) |
3 | opnneilem.1 | . . 3 ⊢ ((𝜑 ∧ 𝑥 = 𝑦) → (𝜓 ↔ 𝜒)) | |
4 | 2, 3 | anbi12d 630 | . 2 ⊢ ((𝜑 ∧ 𝑥 = 𝑦) → ((𝑆 ⊆ 𝑥 ∧ 𝜓) ↔ (𝑆 ⊆ 𝑦 ∧ 𝜒))) |
5 | 4 | cbvrexdva 3392 | 1 ⊢ (𝜑 → (∃𝑥 ∈ 𝐽 (𝑆 ⊆ 𝑥 ∧ 𝜓) ↔ ∃𝑦 ∈ 𝐽 (𝑆 ⊆ 𝑦 ∧ 𝜒))) |
Colors of variables: wff setvar class |
Syntax hints: → wi 4 ↔ wb 205 ∧ wa 395 ∃wrex 3066 ⊆ wss 3891 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1801 ax-4 1815 ax-5 1916 ax-6 1974 ax-7 2014 ax-8 2111 ax-9 2119 ax-ext 2710 |
This theorem depends on definitions: df-bi 206 df-an 396 df-tru 1544 df-ex 1786 df-sb 2071 df-clab 2717 df-cleq 2731 df-clel 2817 df-rex 3071 df-v 3432 df-in 3898 df-ss 3908 |
This theorem is referenced by: opnneirv 46153 opnneil 46155 opnneieqvv 46157 |
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