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Mirrors > Home > MPE Home > Th. List > sseq2 | Structured version Visualization version GIF version |
Description: Equality theorem for the subclass relationship. (Contributed by NM, 25-Jun-1998.) |
Ref | Expression |
---|---|
sseq2 | ⊢ (𝐴 = 𝐵 → (𝐶 ⊆ 𝐴 ↔ 𝐶 ⊆ 𝐵)) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | sstr2 3932 | . . . 4 ⊢ (𝐶 ⊆ 𝐴 → (𝐴 ⊆ 𝐵 → 𝐶 ⊆ 𝐵)) | |
2 | 1 | com12 32 | . . 3 ⊢ (𝐴 ⊆ 𝐵 → (𝐶 ⊆ 𝐴 → 𝐶 ⊆ 𝐵)) |
3 | sstr2 3932 | . . . 4 ⊢ (𝐶 ⊆ 𝐵 → (𝐵 ⊆ 𝐴 → 𝐶 ⊆ 𝐴)) | |
4 | 3 | com12 32 | . . 3 ⊢ (𝐵 ⊆ 𝐴 → (𝐶 ⊆ 𝐵 → 𝐶 ⊆ 𝐴)) |
5 | 2, 4 | anim12i 612 | . 2 ⊢ ((𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐴) → ((𝐶 ⊆ 𝐴 → 𝐶 ⊆ 𝐵) ∧ (𝐶 ⊆ 𝐵 → 𝐶 ⊆ 𝐴))) |
6 | eqss 3940 | . 2 ⊢ (𝐴 = 𝐵 ↔ (𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐴)) | |
7 | dfbi2 474 | . 2 ⊢ ((𝐶 ⊆ 𝐴 ↔ 𝐶 ⊆ 𝐵) ↔ ((𝐶 ⊆ 𝐴 → 𝐶 ⊆ 𝐵) ∧ (𝐶 ⊆ 𝐵 → 𝐶 ⊆ 𝐴))) | |
8 | 5, 6, 7 | 3imtr4i 291 | 1 ⊢ (𝐴 = 𝐵 → (𝐶 ⊆ 𝐴 ↔ 𝐶 ⊆ 𝐵)) |
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