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Theorem rspcdf 3564
Description: Restricted specialization, using implicit substitution. (Contributed by Emmett Weisz, 16-Jan-2020.)
Hypotheses
Ref Expression
rspcdf.1 Ⅎ𝑥𝜑
rspcdf.2 Ⅎ𝑥𝜒
rspcdf.3 (𝜑 → 𝐴 ∈ 𝐵)
rspcdf.4 ((𝜑 ∧ 𝑥 = 𝐴) → (𝜓 ↔ 𝜒))
Assertion
Ref Expression
rspcdf (𝜑 → (∀𝑥 ∈ 𝐵 𝜓 → 𝜒))
Distinct variable groups:   𝑥,𝐴   𝑥,𝐵
Allowed substitution hints:   𝜑(𝑥)   𝜓(𝑥)   𝜒(𝑥)

Proof of Theorem rspcdf
StepHypRef Expression
1 rspcdf.1 . . 3 Ⅎ𝑥𝜑
2 rspcdf.4 . . . 4 ((𝜑 ∧ 𝑥 = 𝐴) → (𝜓 ↔ 𝜒))
32ex 418 . . 3 (𝜑 → (𝑥 = 𝐴 → (𝜓 ↔ 𝜒)))
41, 3alrimi 2250 . 2 (𝜑 → ∀𝑥(𝑥 = 𝐴 → (𝜓 ↔ 𝜒)))
5 rspcdf.3 . 2 (𝜑 → 𝐴 ∈ 𝐵)
6 rspcdf.2 . . 3 Ⅎ𝑥𝜒
76rspct 3563 . 2 (∀𝑥(𝑥 = 𝐴 → (𝜓 ↔ 𝜒)) → (𝐴 ∈ 𝐵 → (∀𝑥 ∈ 𝐵 𝜓 → 𝜒)))
84, 5, 7sylc 66 1 (𝜑 → (∀𝑥 ∈ 𝐵 𝜓 → 𝜒))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ↔ wb 209   ∧ wa 401  ∀wal 1568   = wceq 1570  Ⅎwnf 1816   ∈ wcel 2145  ∀wral 3077
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-10 2178  ax-11 2194  ax-12 2213  ax-ext 2733
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-ex 1813  df-nf 1817  df-cleq 2753  df-clel 2836  df-nfc 2910  df-ral 3078
This theorem is used by:  rspc2daf  33063
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