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Theorem rspcebdv 3571
Description: Restricted existential specialization, using implicit substitution in both directions. (Contributed by AV, 8-Jan-2022.)
Hypotheses
Ref Expression
rspcdv.1 (𝜑 → 𝐴 ∈ 𝐵)
rspcdv.2 ((𝜑 ∧ 𝑥 = 𝐴) → (𝜓 ↔ 𝜒))
rspcebdv.1 ((𝜑 ∧ 𝜓) → 𝑥 = 𝐴)
Assertion
Ref Expression
rspcebdv (𝜑 → (∃𝑥 ∈ 𝐵 𝜓 ↔ 𝜒))
Distinct variable groups:   𝑥,𝐴   𝑥,𝐵   𝜑,𝑥   𝜒,𝑥
Allowed substitution hint:   𝜓(𝑥)

Proof of Theorem rspcebdv
StepHypRef Expression
1 rspcebdv.1 . . . . . . 7 ((𝜑 ∧ 𝜓) → 𝑥 = 𝐴)
2 rspcdv.2 . . . . . . 7 ((𝜑 ∧ 𝑥 = 𝐴) → (𝜓 ↔ 𝜒))
31, 2syldan 603 . . . . . 6 ((𝜑 ∧ 𝜓) → (𝜓 ↔ 𝜒))
43biimpd 232 . . . . 5 ((𝜑 ∧ 𝜓) → (𝜓 → 𝜒))
54expcom 419 . . . 4 (𝜓 → (𝜑 → (𝜓 → 𝜒)))
65pm2.43b 56 . . 3 (𝜑 → (𝜓 → 𝜒))
76rexlimdvw 3169 . 2 (𝜑 → (∃𝑥 ∈ 𝐵 𝜓 → 𝜒))
8 rspcdv.1 . . 3 (𝜑 → 𝐴 ∈ 𝐵)
98, 2rspcedv 3570 . 2 (𝜑 → (𝜒 → ∃𝑥 ∈ 𝐵 𝜓))
107, 9impbid 215 1 (𝜑 → (∃𝑥 ∈ 𝐵 𝜓 ↔ 𝜒))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ↔ wb 209   ∧ wa 401   = wceq 1570   ∈ wcel 2145  ∃wrex 3087
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2733
This proof depends on definitions:  df-bi 210  df-an 402  df-tru 1573  df-ex 1813  df-sb 2100  df-clab 2740  df-cleq 2753  df-clel 2836  df-ral 3078  df-rex 3088
This theorem is used by:  fusgr2wsp2nb  30935
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