Theorem rspcebdv 3570

Description: Restricted existential specialization, using implicit substitution in both directions. (Contributed by AV, 8-Jan-2022.)

Hypotheses

Ref	Expression
rspcdv.1	⊢ (𝜑 → 𝐴 ∈ 𝐵)
rspcdv.2	⊢ ((𝜑 ∧ 𝑥 = 𝐴) → (𝜓 ↔ 𝜒))
rspcebdv.1	⊢ ((𝜑 ∧ 𝜓) → 𝑥 = 𝐴)

Assertion

Ref	Expression
rspcebdv	⊢ (𝜑 → (∃𝑥 ∈ 𝐵 𝜓 ↔ 𝜒))

Distinct variable groups:   𝑥,𝐴   𝑥,𝐵   𝜑,𝑥   𝜒,𝑥

Allowed substitution hint:   𝜓(𝑥)

Proof of Theorem rspcebdv

Step	Hyp	Ref	Expression
1		rspcebdv.1	. . . . . . 7 ⊢ ((𝜑 ∧ 𝜓) → 𝑥 = 𝐴)
2		rspcdv.2	. . . . . . 7 ⊢ ((𝜑 ∧ 𝑥 = 𝐴) → (𝜓 ↔ 𝜒))
3	1, 2	syldan 603	. . . . . 6 ⊢ ((𝜑 ∧ 𝜓) → (𝜓 ↔ 𝜒))
4	3	biimpd 232	. . . . 5 ⊢ ((𝜑 ∧ 𝜓) → (𝜓 → 𝜒))
5	4	expcom 419	. . . 4 ⊢ (𝜓 → (𝜑 → (𝜓 → 𝜒)))
6	5	pm2.43b 56	. . 3 ⊢ (𝜑 → (𝜓 → 𝜒))
7	6	rexlimdvw 3168	. 2 ⊢ (𝜑 → (∃𝑥 ∈ 𝐵 𝜓 → 𝜒))
8		rspcdv.1	. . 3 ⊢ (𝜑 → 𝐴 ∈ 𝐵)
9	8, 2	rspcedv 3569	. 2 ⊢ (𝜑 → (𝜒 → ∃𝑥 ∈ 𝐵 𝜓))
10	7, 9	impbid 215	1 ⊢ (𝜑 → (∃𝑥 ∈ 𝐵 𝜓 ↔ 𝜒))

This proof depends on syntax axioms:   → wi 4   ↔ wb 209   ∧ wa 401   = wceq 1569   ∈ wcel 2144  ∃wrex 3086

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-ext 2732

This proof depends on definitions:  df-bi 210  df-an 402  df-tru 1572  df-ex 1812  df-sb 2099  df-clab 2739  df-cleq 2752  df-clel 2835  df-ral 3077  df-rex 3087

This theorem is used by:  fusgr2wsp2nb  30944