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| Mirrors > Home > MPE Home > Th. List > sb7f | Structured version Visualization version GIF version | ||
| Description: This version of dfsb7 2280 does not require that 𝜑 and 𝑧 be disjoint. This permits it to be used as a definition for substitution in a formalization that omits the logically redundant axiom ax-5 1910, i.e., that does not have the concept of a variable not occurring in a formula. (Definition dfsb1 2486 is also suitable, but its mixing of free and bound variables is distasteful to some logicians.) Usage of this theorem is discouraged because it depends on ax-13 2377. (Contributed by NM, 26-Jul-2006.) (Revised by Mario Carneiro, 6-Oct-2016.) (New usage is discouraged.) |
| Ref | Expression |
|---|---|
| sb7f.1 | ⊢ Ⅎ𝑧𝜑 |
| Ref | Expression |
|---|---|
| sb7f | ⊢ ([𝑦 / 𝑥]𝜑 ↔ ∃𝑧(𝑧 = 𝑦 ∧ ∃𝑥(𝑥 = 𝑧 ∧ 𝜑))) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | sb7f.1 | . . . 4 ⊢ Ⅎ𝑧𝜑 | |
| 2 | 1 | sb5f 2503 | . . 3 ⊢ ([𝑧 / 𝑥]𝜑 ↔ ∃𝑥(𝑥 = 𝑧 ∧ 𝜑)) |
| 3 | 2 | sbbii 2077 | . 2 ⊢ ([𝑦 / 𝑧][𝑧 / 𝑥]𝜑 ↔ [𝑦 / 𝑧]∃𝑥(𝑥 = 𝑧 ∧ 𝜑)) |
| 4 | 1 | sbco2 2516 | . 2 ⊢ ([𝑦 / 𝑧][𝑧 / 𝑥]𝜑 ↔ [𝑦 / 𝑥]𝜑) |
| 5 | sb5 2277 | . 2 ⊢ ([𝑦 / 𝑧]∃𝑥(𝑥 = 𝑧 ∧ 𝜑) ↔ ∃𝑧(𝑧 = 𝑦 ∧ ∃𝑥(𝑥 = 𝑧 ∧ 𝜑))) | |
| 6 | 3, 4, 5 | 3bitr3i 301 | 1 ⊢ ([𝑦 / 𝑥]𝜑 ↔ ∃𝑧(𝑧 = 𝑦 ∧ ∃𝑥(𝑥 = 𝑧 ∧ 𝜑))) |
| Colors of variables: wff setvar class |
| Syntax hints: ↔ wb 206 ∧ wa 395 ∃wex 1779 Ⅎwnf 1783 [wsb 2065 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1795 ax-4 1809 ax-5 1910 ax-6 1967 ax-7 2008 ax-10 2142 ax-11 2158 ax-12 2178 ax-13 2377 |
| This theorem depends on definitions: df-bi 207 df-an 396 df-or 848 df-tru 1543 df-ex 1780 df-nf 1784 df-sb 2066 |
| This theorem is referenced by: sb7h 2531 |
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