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Theorem xrneq2 36842
Description: Equality theorem for the range Cartesian product. (Contributed by Peter Mazsa, 16-Dec-2020.)
Assertion
Ref Expression
xrneq2 (𝐴 = 𝐵 → (𝐶𝐴) = (𝐶𝐵))

Proof of Theorem xrneq2
StepHypRef Expression
1 coeq2 5814 . . 3 (𝐴 = 𝐵 → ((2nd ↾ (V × V)) ∘ 𝐴) = ((2nd ↾ (V × V)) ∘ 𝐵))
21ineq2d 4172 . 2 (𝐴 = 𝐵 → (((1st ↾ (V × V)) ∘ 𝐶) ∩ ((2nd ↾ (V × V)) ∘ 𝐴)) = (((1st ↾ (V × V)) ∘ 𝐶) ∩ ((2nd ↾ (V × V)) ∘ 𝐵)))
3 df-xrn 36833 . 2 (𝐶𝐴) = (((1st ↾ (V × V)) ∘ 𝐶) ∩ ((2nd ↾ (V × V)) ∘ 𝐴))
4 df-xrn 36833 . 2 (𝐶𝐵) = (((1st ↾ (V × V)) ∘ 𝐶) ∩ ((2nd ↾ (V × V)) ∘ 𝐵))
52, 3, 43eqtr4g 2801 1 (𝐴 = 𝐵 → (𝐶𝐴) = (𝐶𝐵))
Colors of variables: wff setvar class
Syntax hints:  wi 4   = wceq 1541  Vcvv 3445  cin 3909   × cxp 5631  ccnv 5632  cres 5635  ccom 5637  1st c1st 7919  2nd c2nd 7920  cxrn 36633
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1913  ax-6 1971  ax-7 2011  ax-8 2108  ax-9 2116  ax-ext 2707
This theorem depends on definitions:  df-bi 206  df-an 397  df-tru 1544  df-ex 1782  df-sb 2068  df-clab 2714  df-cleq 2728  df-clel 2814  df-rab 3408  df-v 3447  df-in 3917  df-ss 3927  df-br 5106  df-opab 5168  df-co 5642  df-xrn 36833
This theorem is referenced by:  xrneq2i  36843  xrneq2d  36844  xrneq12  36845
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