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Theorem xrneq2 38650
Description: Equality theorem for the range Cartesian product. (Contributed by Peter Mazsa, 16-Dec-2020.)
Assertion
Ref Expression
xrneq2 (𝐴 = 𝐵 → (𝐶𝐴) = (𝐶𝐵))

Proof of Theorem xrneq2
StepHypRef Expression
1 coeq2 5815 . . 3 (𝐴 = 𝐵 → ((2nd ↾ (V × V)) ∘ 𝐴) = ((2nd ↾ (V × V)) ∘ 𝐵))
21ineq2d 4174 . 2 (𝐴 = 𝐵 → (((1st ↾ (V × V)) ∘ 𝐶) ∩ ((2nd ↾ (V × V)) ∘ 𝐴)) = (((1st ↾ (V × V)) ∘ 𝐶) ∩ ((2nd ↾ (V × V)) ∘ 𝐵)))
3 df-xrn 38631 . 2 (𝐶𝐴) = (((1st ↾ (V × V)) ∘ 𝐶) ∩ ((2nd ↾ (V × V)) ∘ 𝐴))
4 df-xrn 38631 . 2 (𝐶𝐵) = (((1st ↾ (V × V)) ∘ 𝐶) ∩ ((2nd ↾ (V × V)) ∘ 𝐵))
52, 3, 43eqtr4g 2797 1 (𝐴 = 𝐵 → (𝐶𝐴) = (𝐶𝐵))
Colors of variables: wff setvar class
Syntax hints:  wi 4   = wceq 1542  Vcvv 3442  cin 3902   × cxp 5630  ccnv 5631  cres 5634  ccom 5636  1st c1st 7941  2nd c2nd 7942  cxrn 38425
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1912  ax-6 1969  ax-7 2010  ax-8 2116  ax-9 2124  ax-ext 2709
This theorem depends on definitions:  df-bi 207  df-an 396  df-tru 1545  df-ex 1782  df-sb 2069  df-clab 2716  df-cleq 2729  df-clel 2812  df-rab 3402  df-in 3910  df-ss 3920  df-br 5101  df-opab 5163  df-co 5641  df-xrn 38631
This theorem is referenced by:  xrneq2i  38651  xrneq2d  38652  xrneq12  38653
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