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Mirrors > Home > NFE Home > Th. List > elprg | GIF version |
Description: A member of an unordered pair of classes is one or the other of them. Exercise 1 of [TakeutiZaring] p. 15, generalized. (Contributed by NM, 13-Sep-1995.) |
Ref | Expression |
---|---|
elprg | ⊢ (A ∈ V → (A ∈ {B, C} ↔ (A = B ∨ A = C))) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | eqeq1 2359 | . . 3 ⊢ (x = A → (x = B ↔ A = B)) | |
2 | eqeq1 2359 | . . 3 ⊢ (x = A → (x = C ↔ A = C)) | |
3 | 1, 2 | orbi12d 690 | . 2 ⊢ (x = A → ((x = B ∨ x = C) ↔ (A = B ∨ A = C))) |
4 | dfpr2 3750 | . 2 ⊢ {B, C} = {x ∣ (x = B ∨ x = C)} | |
5 | 3, 4 | elab2g 2988 | 1 ⊢ (A ∈ V → (A ∈ {B, C} ↔ (A = B ∨ A = C))) |
Colors of variables: wff setvar class |
Syntax hints: → wi 4 ↔ wb 176 ∨ wo 357 = wceq 1642 ∈ wcel 1710 {cpr 3739 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1546 ax-5 1557 ax-17 1616 ax-9 1654 ax-8 1675 ax-6 1729 ax-7 1734 ax-11 1746 ax-12 1925 ax-ext 2334 |
This theorem depends on definitions: df-bi 177 df-or 359 df-an 360 df-nan 1288 df-tru 1319 df-ex 1542 df-nf 1545 df-sb 1649 df-clab 2340 df-cleq 2346 df-clel 2349 df-nfc 2479 df-v 2862 df-nin 3212 df-compl 3213 df-un 3215 df-sn 3742 df-pr 3743 |
This theorem is referenced by: elpr 3752 elpr2 3753 elpri 3754 eltpg 3770 ifpr 3775 prid1g 3826 |
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