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| Mirrors > Home > ILE Home > Th. List > eqsb1 | Unicode version | ||
| Description: Substitution for the left-hand side in an equality. Class version of equsb3 1970. (Contributed by Rodolfo Medina, 28-Apr-2010.) |
| Ref | Expression |
|---|---|
| eqsb1 |
|
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | eqsb1lem 2299 |
. . 3
| |
| 2 | 1 | sbbii 1779 |
. 2
|
| 3 | nfv 1542 |
. . 3
| |
| 4 | 3 | sbco2 1984 |
. 2
|
| 5 | eqsb1lem 2299 |
. 2
| |
| 6 | 2, 4, 5 | 3bitr3i 210 |
1
|
| Colors of variables: wff set class |
| Syntax hints: |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-io 710 ax-5 1461 ax-7 1462 ax-gen 1463 ax-ie1 1507 ax-ie2 1508 ax-8 1518 ax-10 1519 ax-11 1520 ax-i12 1521 ax-bndl 1523 ax-4 1524 ax-17 1540 ax-i9 1544 ax-ial 1548 ax-i5r 1549 ax-ext 2178 |
| This theorem depends on definitions: df-bi 117 df-nf 1475 df-sb 1777 df-cleq 2189 |
| This theorem is referenced by: pm13.183 2902 eqsbc1 3029 |
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