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Theorem eqsb1 2279
Description: Substitution for the left-hand side in an equality. Class version of equsb3 1949. (Contributed by Rodolfo Medina, 28-Apr-2010.)
Assertion
Ref Expression
eqsb1 ([𝑦 / 𝑥]𝑥 = 𝐴𝑦 = 𝐴)
Distinct variable group:   𝑥,𝐴
Allowed substitution hint:   𝐴(𝑦)

Proof of Theorem eqsb1
Dummy variable 𝑤 is distinct from all other variables.
StepHypRef Expression
1 eqsb1lem 2278 . . 3 ([𝑤 / 𝑥]𝑥 = 𝐴𝑤 = 𝐴)
21sbbii 1763 . 2 ([𝑦 / 𝑤][𝑤 / 𝑥]𝑥 = 𝐴 ↔ [𝑦 / 𝑤]𝑤 = 𝐴)
3 nfv 1526 . . 3 𝑤 𝑥 = 𝐴
43sbco2 1963 . 2 ([𝑦 / 𝑤][𝑤 / 𝑥]𝑥 = 𝐴 ↔ [𝑦 / 𝑥]𝑥 = 𝐴)
5 eqsb1lem 2278 . 2 ([𝑦 / 𝑤]𝑤 = 𝐴𝑦 = 𝐴)
62, 4, 53bitr3i 210 1 ([𝑦 / 𝑥]𝑥 = 𝐴𝑦 = 𝐴)
Colors of variables: wff set class
Syntax hints:  wb 105   = wceq 1353  [wsb 1760
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 709  ax-5 1445  ax-7 1446  ax-gen 1447  ax-ie1 1491  ax-ie2 1492  ax-8 1502  ax-10 1503  ax-11 1504  ax-i12 1505  ax-bndl 1507  ax-4 1508  ax-17 1524  ax-i9 1528  ax-ial 1532  ax-i5r 1533  ax-ext 2157
This theorem depends on definitions:  df-bi 117  df-nf 1459  df-sb 1761  df-cleq 2168
This theorem is referenced by:  pm13.183  2873  eqsbc1  3000
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