ILE Home Intuitionistic Logic Explorer < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  ILE Home  >  Th. List  >  nfald Unicode version

Theorem nfald 1806
Description: If  x is not free in  ph, it is not free in  A. y ph. (Contributed by Mario Carneiro, 24-Sep-2016.) (Proof shortened by Wolf Lammen, 6-Jan-2018.)
Hypotheses
Ref Expression
nfald.1  |-  F/ y
ph
nfald.2  |-  ( ph  ->  F/ x ps )
Assertion
Ref Expression
nfald  |-  ( ph  ->  F/ x A. y ps )

Proof of Theorem nfald
StepHypRef Expression
1 nfald.1 . . . 4  |-  F/ y
ph
21nfri 1565 . . 3  |-  ( ph  ->  A. y ph )
3 nfald.2 . . 3  |-  ( ph  ->  F/ x ps )
42, 3alrimih 1515 . 2  |-  ( ph  ->  A. y F/ x ps )
5 nfnf1 1590 . . . 4  |-  F/ x F/ x ps
65nfal 1622 . . 3  |-  F/ x A. y F/ x ps
7 hba1 1586 . . . 4  |-  ( A. y F/ x ps  ->  A. y A. y F/ x ps )
8 sp 1557 . . . . 5  |-  ( A. y F/ x ps  ->  F/ x ps )
98nfrd 1566 . . . 4  |-  ( A. y F/ x ps  ->  ( ps  ->  A. x ps ) )
107, 9hbald 1537 . . 3  |-  ( A. y F/ x ps  ->  ( A. y ps  ->  A. x A. y ps ) )
116, 10nfd 1569 . 2  |-  ( A. y F/ x ps  ->  F/ x A. y ps )
124, 11syl 14 1  |-  ( ph  ->  F/ x A. y ps )
Colors of variables: wff set class
Syntax hints:    -> wi 4   A.wal 1393   F/wnf 1506
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1493  ax-7 1494  ax-gen 1495  ax-4 1556  ax-ial 1580
This theorem depends on definitions:  df-bi 117  df-nf 1507
This theorem is referenced by:  dvelimALT  2061  dvelimfv  2062  nfeudv  2092  nfeqd  2387  nfraldw  2562  nfraldxy  2563  nfiotadw  5281  nfixpxy  6864  bdsepnft  16250
  Copyright terms: Public domain W3C validator