Theorem nfnf1 1532

Description: x is not free in F/ x ph. (Contributed by Mario Carneiro, 11-Aug-2016.)

Assertion

Ref	Expression
nfnf1	|- F/ x F/ x ph

Proof of Theorem nfnf1

Step	Hyp	Ref	Expression
1		df-nf 1449	. 2 |- ( F/ x ph <-> A. x ( ph -> A. x ph ) )
2		nfa1 1529	. 2 |- F/ x A. x ( ph -> A. x ph )
3	1, 2	nfxfr 1462	1 |- F/ x F/ x ph

Syntax hints:   -> wi 4   A.wal 1341   F/wnf 1448

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1435  ax-gen 1437  ax-ial 1522

This theorem depends on definitions:  df-bi 116  df-nf 1449

This theorem is referenced by:  nfimd  1573  nfnt  1644  nfald  1748  equs5or  1818  sbcomxyyz  1960  nfsb4t  2002  nfnfc1  2311  nfabdw  2327  sbcnestgf  3096  dfnfc2  3807  bdsepnft  13769  setindft  13847  strcollnft  13866