Theorem sbcne12g 3090

Description: Distribute proper substitution through an inequality. (Contributed by Andrew Salmon, 18-Jun-2011.)

Assertion

Ref	Expression
sbcne12g	|- ( A e. V -> ( [. A / x ]. B =/= C <-> [_ A / x ]_ B =/= [_ A / x ]_ C ) )

Proof of Theorem sbcne12g

Step	Hyp	Ref	Expression
1		sbceqg 3088	. . 3 |- ( A e. V -> ( [. A / x ]. B = C <-> [_ A / x ]_ B = [_ A / x ]_ C ) )
2	1	notbid 668	. 2 |- ( A e. V -> ( -. [. A / x ]. B = C <-> -. [_ A / x ]_ B = [_ A / x ]_ C ) )
3		df-ne 2361	. . . . 5 |- ( B =/= C <-> -. B = C )
4	3	sbcbii 3037	. . . 4 |- ( [. A / x ]. B =/= C <-> [. A / x ]. -. B = C )
5		sbcng 3018	. . . 4 |- ( A e. V -> ( [. A / x ]. -. B = C <-> -. [. A / x ]. B = C ) )
6	4, 5	bitrid 192	. . 3 |- ( A e. V -> ( [. A / x ]. B =/= C <-> -. [. A / x ]. B = C ) )
7		df-ne 2361	. . . 4 |- ( [_ A / x ]_ B =/= [_ A / x ]_ C <-> -. [_ A / x ]_ B = [_ A / x ]_ C )
8	7	a1i 9	. . 3 |- ( A e. V -> ( [_ A / x ]_ B =/= [_ A / x ]_ C <-> -. [_ A / x ]_ B = [_ A / x ]_ C ) )
9	6, 8	bibi12d 235	. 2 |- ( A e. V -> ( ( [. A / x ]. B =/= C <-> [_ A / x ]_ B =/= [_ A / x ]_ C ) <-> ( -. [. A / x ]. B = C <-> -. [_ A / x ]_ B = [_ A / x ]_ C ) ) )
10	2, 9	mpbird 167	1 |- ( A e. V -> ( [. A / x ]. B =/= C <-> [_ A / x ]_ B =/= [_ A / x ]_ C ) )

Syntax hints:   -. wn 3   -> wi 4   <-> wb 105   = wceq 1364   e. wcel 2160   =/= wne 2360   [.wsbc 2977   [_csb 3072

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 615  ax-in2 616  ax-io 710  ax-5 1458  ax-7 1459  ax-gen 1460  ax-ie1 1504  ax-ie2 1505  ax-8 1515  ax-10 1516  ax-11 1517  ax-i12 1518  ax-bndl 1520  ax-4 1521  ax-17 1537  ax-i9 1541  ax-ial 1545  ax-i5r 1546  ax-ext 2171

This theorem depends on definitions:  df-bi 117  df-tru 1367  df-fal 1370  df-nf 1472  df-sb 1774  df-clab 2176  df-cleq 2182  df-clel 2185  df-nfc 2321  df-ne 2361  df-v 2754  df-sbc 2978  df-csb 3073

This theorem is referenced by: (None)