Theorem sbcne12g 3119

Description: Distribute proper substitution through an inequality. (Contributed by Andrew Salmon, 18-Jun-2011.)

Assertion

Ref	Expression
sbcne12g	|- ( A e. V -> ( [. A / x ]. B =/= C <-> [_ A / x ]_ B =/= [_ A / x ]_ C ) )

Proof of Theorem sbcne12g

Step	Hyp	Ref	Expression
1		sbceqg 3117	. . 3 |- ( A e. V -> ( [. A / x ]. B = C <-> [_ A / x ]_ B = [_ A / x ]_ C ) )
2	1	notbid 669	. 2 |- ( A e. V -> ( -. [. A / x ]. B = C <-> -. [_ A / x ]_ B = [_ A / x ]_ C ) )
3		df-ne 2379	. . . . 5 |- ( B =/= C <-> -. B = C )
4	3	sbcbii 3065	. . . 4 |- ( [. A / x ]. B =/= C <-> [. A / x ]. -. B = C )
5		sbcng 3046	. . . 4 |- ( A e. V -> ( [. A / x ]. -. B = C <-> -. [. A / x ]. B = C ) )
6	4, 5	bitrid 192	. . 3 |- ( A e. V -> ( [. A / x ]. B =/= C <-> -. [. A / x ]. B = C ) )
7		df-ne 2379	. . . 4 |- ( [_ A / x ]_ B =/= [_ A / x ]_ C <-> -. [_ A / x ]_ B = [_ A / x ]_ C )
8	7	a1i 9	. . 3 |- ( A e. V -> ( [_ A / x ]_ B =/= [_ A / x ]_ C <-> -. [_ A / x ]_ B = [_ A / x ]_ C ) )
9	6, 8	bibi12d 235	. 2 |- ( A e. V -> ( ( [. A / x ]. B =/= C <-> [_ A / x ]_ B =/= [_ A / x ]_ C ) <-> ( -. [. A / x ]. B = C <-> -. [_ A / x ]_ B = [_ A / x ]_ C ) ) )
10	2, 9	mpbird 167	1 |- ( A e. V -> ( [. A / x ]. B =/= C <-> [_ A / x ]_ B =/= [_ A / x ]_ C ) )

Syntax hints:   -. wn 3   -> wi 4   <-> wb 105   = wceq 1373   e. wcel 2178   =/= wne 2378   [.wsbc 3005   [_csb 3101

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 615  ax-in2 616  ax-io 711  ax-5 1471  ax-7 1472  ax-gen 1473  ax-ie1 1517  ax-ie2 1518  ax-8 1528  ax-10 1529  ax-11 1530  ax-i12 1531  ax-bndl 1533  ax-4 1534  ax-17 1550  ax-i9 1554  ax-ial 1558  ax-i5r 1559  ax-ext 2189

This theorem depends on definitions:  df-bi 117  df-tru 1376  df-fal 1379  df-nf 1485  df-sb 1787  df-clab 2194  df-cleq 2200  df-clel 2203  df-nfc 2339  df-ne 2379  df-v 2778  df-sbc 3006  df-csb 3102

This theorem is referenced by: (None)