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Theorem sseq0 3501
Description: A subclass of an empty class is empty. (Contributed by NM, 7-Mar-2007.) (Proof shortened by Andrew Salmon, 26-Jun-2011.)
Assertion
Ref Expression
sseq0  |-  ( ( A  C_  B  /\  B  =  (/) )  ->  A  =  (/) )

Proof of Theorem sseq0
StepHypRef Expression
1 sseq2 3216 . . 3  |-  ( B  =  (/)  ->  ( A 
C_  B  <->  A  C_  (/) ) )
2 ss0 3500 . . 3  |-  ( A 
C_  (/)  ->  A  =  (/) )
31, 2biimtrdi 163 . 2  |-  ( B  =  (/)  ->  ( A 
C_  B  ->  A  =  (/) ) )
43impcom 125 1  |-  ( ( A  C_  B  /\  B  =  (/) )  ->  A  =  (/) )
Colors of variables: wff set class
Syntax hints:    -> wi 4    /\ wa 104    = wceq 1372    C_ wss 3165   (/)c0 3459
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 615  ax-in2 616  ax-io 710  ax-5 1469  ax-7 1470  ax-gen 1471  ax-ie1 1515  ax-ie2 1516  ax-8 1526  ax-10 1527  ax-11 1528  ax-i12 1529  ax-bndl 1531  ax-4 1532  ax-17 1548  ax-i9 1552  ax-ial 1556  ax-i5r 1557  ax-ext 2186
This theorem depends on definitions:  df-bi 117  df-tru 1375  df-nf 1483  df-sb 1785  df-clab 2191  df-cleq 2197  df-clel 2200  df-nfc 2336  df-v 2773  df-dif 3167  df-in 3171  df-ss 3178  df-nul 3460
This theorem is referenced by:  ssn0  3502  ssdifin0  3541  fieq0  7060  fisumss  11622  strleund  12854  strleun  12855
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