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Theorem sseq0 3554
Description: A subclass of an empty class is empty. (Contributed by NM, 7-Mar-2007.) (Proof shortened by Andrew Salmon, 26-Jun-2011.)
Assertion
Ref Expression
sseq0  |-  ( ( A  C_  B  /\  B  =  (/) )  ->  A  =  (/) )

Proof of Theorem sseq0
StepHypRef Expression
1 sseq2 3266 . . 3  |-  ( B  =  (/)  ->  ( A 
C_  B  <->  A  C_  (/) ) )
2 ss0 3553 . . 3  |-  ( A 
C_  (/)  ->  A  =  (/) )
31, 2biimtrdi 163 . 2  |-  ( B  =  (/)  ->  ( A 
C_  B  ->  A  =  (/) ) )
43impcom 125 1  |-  ( ( A  C_  B  /\  B  =  (/) )  ->  A  =  (/) )
Colors of variables: wff set class
Syntax hints:    -> wi 4    /\ wa 104    = wceq 1398    C_ wss 3214   (/)c0 3512
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 619  ax-in2 620  ax-io 717  ax-5 1496  ax-7 1497  ax-gen 1498  ax-ie1 1542  ax-ie2 1543  ax-8 1553  ax-10 1554  ax-11 1555  ax-i12 1556  ax-bndl 1558  ax-4 1559  ax-17 1575  ax-i9 1579  ax-ial 1583  ax-i5r 1584  ax-ext 2216
This theorem depends on definitions:  df-bi 117  df-tru 1401  df-nf 1510  df-sb 1812  df-clab 2221  df-cleq 2227  df-clel 2230  df-nfc 2375  df-v 2817  df-dif 3216  df-in 3220  df-ss 3227  df-nul 3513
This theorem is referenced by:  ssn0  3555  ssdifin0  3595  fieq0  7276  fisumss  12103  strleund  13400  strleun  13401
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