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Theorem andir 827
Description: Distributive law for conjunction. (Contributed by NM, 12-Aug-1994.)
Assertion
Ref Expression
andir (((𝜑𝜓) ∧ 𝜒) ↔ ((𝜑𝜒) ∨ (𝜓𝜒)))

Proof of Theorem andir
StepHypRef Expression
1 andi 826 . 2 ((𝜒 ∧ (𝜑𝜓)) ↔ ((𝜒𝜑) ∨ (𝜒𝜓)))
2 ancom 266 . 2 (((𝜑𝜓) ∧ 𝜒) ↔ (𝜒 ∧ (𝜑𝜓)))
3 ancom 266 . . 3 ((𝜑𝜒) ↔ (𝜒𝜑))
4 ancom 266 . . 3 ((𝜓𝜒) ↔ (𝜒𝜓))
53, 4orbi12i 772 . 2 (((𝜑𝜒) ∨ (𝜓𝜒)) ↔ ((𝜒𝜑) ∨ (𝜒𝜓)))
61, 2, 53bitr4i 212 1 (((𝜑𝜓) ∧ 𝜒) ↔ ((𝜑𝜒) ∨ (𝜓𝜒)))
Colors of variables: wff set class
Syntax hints:  wa 104  wb 105  wo 716
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 717
This theorem depends on definitions:  df-bi 117
This theorem is referenced by:  anddi  829  excxor  1423  xordc1  1438  sbequilem  1886  rexun  3389  rabun2  3488  reuun2  3492  xpundir  4789  coundi  5245  mptun  5471  tpostpos  6473  ltxr  10054  pythagtriplem2  12902  pythagtrip  12919  vtxdfifiun  16221
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