Theorem andir 827

Description: Distributive law for conjunction. (Contributed by NM, 12-Aug-1994.)

Assertion

Ref	Expression
andir	⊢ (((𝜑 ∨ 𝜓) ∧ 𝜒) ↔ ((𝜑 ∧ 𝜒) ∨ (𝜓 ∧ 𝜒)))

Proof of Theorem andir

Step	Hyp	Ref	Expression
1		andi 826	. 2 ⊢ ((𝜒 ∧ (𝜑 ∨ 𝜓)) ↔ ((𝜒 ∧ 𝜑) ∨ (𝜒 ∧ 𝜓)))
2		ancom 266	. 2 ⊢ (((𝜑 ∨ 𝜓) ∧ 𝜒) ↔ (𝜒 ∧ (𝜑 ∨ 𝜓)))
3		ancom 266	. . 3 ⊢ ((𝜑 ∧ 𝜒) ↔ (𝜒 ∧ 𝜑))
4		ancom 266	. . 3 ⊢ ((𝜓 ∧ 𝜒) ↔ (𝜒 ∧ 𝜓))
5	3, 4	orbi12i 772	. 2 ⊢ (((𝜑 ∧ 𝜒) ∨ (𝜓 ∧ 𝜒)) ↔ ((𝜒 ∧ 𝜑) ∨ (𝜒 ∧ 𝜓)))
6	1, 2, 5	3bitr4i 212	1 ⊢ (((𝜑 ∨ 𝜓) ∧ 𝜒) ↔ ((𝜑 ∧ 𝜒) ∨ (𝜓 ∧ 𝜒)))

Syntax hints:   ∧ wa 104   ↔ wb 105   ∨ wo 716

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 717

This theorem depends on definitions:  df-bi 117

This theorem is referenced by:  anddi  829  excxor  1423  xordc1  1438  sbequilem  1887  rexun  3399  rabun2  3500  reuun2  3504  xpundir  4807  coundi  5264  mptun  5490  tpostpos  6495  ltxr  10108  hashfibclem  11206  pythagtriplem2  12964  pythagtrip  12981  vtxdfifiun  16292