Theorem an6 1447

Description: Rearrangement of 6 conjuncts. (Contributed by NM, 13-Mar-1995.)

Assertion

Ref	Expression
an6	⊢ (((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ (𝜃 ∧ 𝜏 ∧ 𝜂)) ↔ ((𝜑 ∧ 𝜃) ∧ (𝜓 ∧ 𝜏) ∧ (𝜒 ∧ 𝜂)))

Proof of Theorem an6

Step	Hyp	Ref	Expression
1		an4 656	. . 3 ⊢ ((((𝜑 ∧ 𝜓) ∧ 𝜒) ∧ ((𝜃 ∧ 𝜏) ∧ 𝜂)) ↔ (((𝜑 ∧ 𝜓) ∧ (𝜃 ∧ 𝜏)) ∧ (𝜒 ∧ 𝜂)))
2		an4 656	. . . 4 ⊢ (((𝜑 ∧ 𝜓) ∧ (𝜃 ∧ 𝜏)) ↔ ((𝜑 ∧ 𝜃) ∧ (𝜓 ∧ 𝜏)))
3	2	anbi1i 624	. . 3 ⊢ ((((𝜑 ∧ 𝜓) ∧ (𝜃 ∧ 𝜏)) ∧ (𝜒 ∧ 𝜂)) ↔ (((𝜑 ∧ 𝜃) ∧ (𝜓 ∧ 𝜏)) ∧ (𝜒 ∧ 𝜂)))
4	1, 3	bitri 275	. 2 ⊢ ((((𝜑 ∧ 𝜓) ∧ 𝜒) ∧ ((𝜃 ∧ 𝜏) ∧ 𝜂)) ↔ (((𝜑 ∧ 𝜃) ∧ (𝜓 ∧ 𝜏)) ∧ (𝜒 ∧ 𝜂)))
5		df-3an 1089	. . 3 ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) ↔ ((𝜑 ∧ 𝜓) ∧ 𝜒))
6		df-3an 1089	. . 3 ⊢ ((𝜃 ∧ 𝜏 ∧ 𝜂) ↔ ((𝜃 ∧ 𝜏) ∧ 𝜂))
7	5, 6	anbi12i 628	. 2 ⊢ (((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ (𝜃 ∧ 𝜏 ∧ 𝜂)) ↔ (((𝜑 ∧ 𝜓) ∧ 𝜒) ∧ ((𝜃 ∧ 𝜏) ∧ 𝜂)))
8		df-3an 1089	. 2 ⊢ (((𝜑 ∧ 𝜃) ∧ (𝜓 ∧ 𝜏) ∧ (𝜒 ∧ 𝜂)) ↔ (((𝜑 ∧ 𝜃) ∧ (𝜓 ∧ 𝜏)) ∧ (𝜒 ∧ 𝜂)))
9	4, 7, 8	3bitr4i 303	1 ⊢ (((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ (𝜃 ∧ 𝜏 ∧ 𝜂)) ↔ ((𝜑 ∧ 𝜃) ∧ (𝜓 ∧ 𝜏) ∧ (𝜒 ∧ 𝜂)))

Syntax hints:   ↔ wb 206   ∧ wa 395   ∧ w3a 1087

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 207  df-an 396  df-3an 1089

This theorem is referenced by:  3an6  1448  poxp3  8175  elfzuzb  13558  fzadd2  13599  ptbasin  23585  iimulcl  24966  nb3grpr  29399  nb3grpr2  29400  txpconn  35237  paddasslem9  39830  paddasslem10  39831  gboge9  47751