Theorem bj-gabeqd 37772

Description: Equality of generalized class abstractions. Deduction form. (Contributed by BJ, 4-Oct-2024.)

Hypotheses

Ref	Expression
bj-gabeqd.nf	⊢ (𝜑 → ∀𝑥𝜑)
bj-gabeqd.c	⊢ (𝜑 → 𝐴 = 𝐵)
bj-gabeqd.f	⊢ (𝜑 → (𝜓 ↔ 𝜒))

Assertion

Ref	Expression
bj-gabeqd	⊢ (𝜑 → {𝐴 ∣ 𝑥 ∣ 𝜓} = {𝐵 ∣ 𝑥 ∣ 𝜒})

Proof of Theorem bj-gabeqd

Step	Hyp	Ref	Expression
1		bj-gabeqd.nf	. . 3 ⊢ (𝜑 → ∀𝑥𝜑)
2		bj-gabeqd.c	. . 3 ⊢ (𝜑 → 𝐴 = 𝐵)
3		bj-gabeqd.f	. . . 4 ⊢ (𝜑 → (𝜓 ↔ 𝜒))
4	3	biimpd 232	. . 3 ⊢ (𝜑 → (𝜓 → 𝜒))
5	1, 2, 4	bj-gabssd 37771	. 2 ⊢ (𝜑 → {𝐴 ∣ 𝑥 ∣ 𝜓} ⊆ {𝐵 ∣ 𝑥 ∣ 𝜒})
6	2	eqcomd 2766	. . 3 ⊢ (𝜑 → 𝐵 = 𝐴)
7	3	biimprd 251	. . 3 ⊢ (𝜑 → (𝜒 → 𝜓))
8	1, 6, 7	bj-gabssd 37771	. 2 ⊢ (𝜑 → {𝐵 ∣ 𝑥 ∣ 𝜒} ⊆ {𝐴 ∣ 𝑥 ∣ 𝜓})
9	5, 8	eqssd 3947	1 ⊢ (𝜑 → {𝐴 ∣ 𝑥 ∣ 𝜓} = {𝐵 ∣ 𝑥 ∣ 𝜒})

This proof depends on syntax axioms:   → wi 4   ↔ wb 209  ∀wal 1568   = wceq 1570  {bj-cgab 37768

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-10 2178  ax-11 2194  ax-12 2213  ax-ext 2732

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-ex 1813  df-nf 1817  df-sb 2100  df-clab 2739  df-cleq 2752  df-clel 2835  df-nfc 2909  df-ss 3915  df-bj-gab 37769

This theorem is used by: (None)