Theorem bj-gabeqd 36121

Description: Equality of generalized class abstractions. Deduction form. (Contributed by BJ, 4-Oct-2024.)

Hypotheses

Ref	Expression
bj-gabeqd.nf	⊢ (𝜑 → ∀𝑥𝜑)
bj-gabeqd.c	⊢ (𝜑 → 𝐴 = 𝐵)
bj-gabeqd.f	⊢ (𝜑 → (𝜓 ↔ 𝜒))

Assertion

Ref	Expression
bj-gabeqd	⊢ (𝜑 → {𝐴 ∣ 𝑥 ∣ 𝜓} = {𝐵 ∣ 𝑥 ∣ 𝜒})

Proof of Theorem bj-gabeqd

Step	Hyp	Ref	Expression
1		bj-gabeqd.nf	. . 3 ⊢ (𝜑 → ∀𝑥𝜑)
2		bj-gabeqd.c	. . 3 ⊢ (𝜑 → 𝐴 = 𝐵)
3		bj-gabeqd.f	. . . 4 ⊢ (𝜑 → (𝜓 ↔ 𝜒))
4	3	biimpd 228	. . 3 ⊢ (𝜑 → (𝜓 → 𝜒))
5	1, 2, 4	bj-gabssd 36120	. 2 ⊢ (𝜑 → {𝐴 ∣ 𝑥 ∣ 𝜓} ⊆ {𝐵 ∣ 𝑥 ∣ 𝜒})
6	2	eqcomd 2737	. . 3 ⊢ (𝜑 → 𝐵 = 𝐴)
7	3	biimprd 247	. . 3 ⊢ (𝜑 → (𝜒 → 𝜓))
8	1, 6, 7	bj-gabssd 36120	. 2 ⊢ (𝜑 → {𝐵 ∣ 𝑥 ∣ 𝜒} ⊆ {𝐴 ∣ 𝑥 ∣ 𝜓})
9	5, 8	eqssd 3999	1 ⊢ (𝜑 → {𝐴 ∣ 𝑥 ∣ 𝜓} = {𝐵 ∣ 𝑥 ∣ 𝜒})

Syntax hints:   → wi 4   ↔ wb 205  ∀wal 1538   = wceq 1540  {bj-cgab 36117

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1912  ax-6 1970  ax-7 2010  ax-8 2107  ax-9 2115  ax-10 2136  ax-11 2153  ax-12 2170  ax-ext 2702

This theorem depends on definitions:  df-bi 206  df-an 396  df-or 845  df-tru 1543  df-ex 1781  df-nf 1785  df-sb 2067  df-clab 2709  df-cleq 2723  df-clel 2809  df-nfc 2884  df-v 3475  df-in 3955  df-ss 3965  df-bj-gab 36118

This theorem is referenced by: (None)