| Mathbox for Peter Mazsa |
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| Mirrors > Home > MPE Home > Th. List > Mathboxes > coideq | Structured version Visualization version GIF version | ||
| Description: Equality theorem for composition of two classes. (Contributed by Peter Mazsa, 23-Sep-2021.) |
| Ref | Expression |
|---|---|
| coideq | ⊢ (𝐴 = 𝐵 → (𝐴 ∘ 𝐴) = (𝐵 ∘ 𝐵)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | coeq1 5799 | . 2 ⊢ (𝐴 = 𝐵 → (𝐴 ∘ 𝐴) = (𝐵 ∘ 𝐴)) | |
| 2 | coeq2 5800 | . 2 ⊢ (𝐴 = 𝐵 → (𝐵 ∘ 𝐴) = (𝐵 ∘ 𝐵)) | |
| 3 | 1, 2 | eqtrd 2774 | 1 ⊢ (𝐴 = 𝐵 → (𝐴 ∘ 𝐴) = (𝐵 ∘ 𝐵)) |
| Colors of variables: wff setvar class |
| Syntax hints: → wi 4 = wceq 1547 ∘ ccom 5622 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1802 ax-4 1816 ax-5 1917 ax-6 1974 ax-7 2015 ax-8 2121 ax-9 2129 ax-ext 2711 |
| This theorem depends on definitions: df-bi 208 df-an 397 df-ex 1787 df-sb 2074 df-clab 2718 df-cleq 2731 df-clel 2814 df-ss 3900 df-br 5073 df-opab 5135 df-co 5627 |
| This theorem is referenced by: eltrrels2 39030 trreleq 39033 eleqvrels2 39043 |
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