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Mirrors > Home > MPE Home > Th. List > Mathboxes > coideq | Structured version Visualization version GIF version |
Description: Equality theorem for composition of two classes. (Contributed by Peter Mazsa, 23-Sep-2021.) |
Ref | Expression |
---|---|
coideq | ⊢ (𝐴 = 𝐵 → (𝐴 ∘ 𝐴) = (𝐵 ∘ 𝐵)) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | coeq1 5755 | . 2 ⊢ (𝐴 = 𝐵 → (𝐴 ∘ 𝐴) = (𝐵 ∘ 𝐴)) | |
2 | coeq2 5756 | . 2 ⊢ (𝐴 = 𝐵 → (𝐵 ∘ 𝐴) = (𝐵 ∘ 𝐵)) | |
3 | 1, 2 | eqtrd 2778 | 1 ⊢ (𝐴 = 𝐵 → (𝐴 ∘ 𝐴) = (𝐵 ∘ 𝐵)) |
Colors of variables: wff setvar class |
Syntax hints: → wi 4 = wceq 1539 ∘ ccom 5584 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1799 ax-4 1813 ax-5 1914 ax-6 1972 ax-7 2012 ax-8 2110 ax-9 2118 ax-ext 2709 |
This theorem depends on definitions: df-bi 206 df-an 396 df-tru 1542 df-ex 1784 df-sb 2069 df-clab 2716 df-cleq 2730 df-clel 2817 df-v 3424 df-in 3890 df-ss 3900 df-br 5071 df-opab 5133 df-co 5589 |
This theorem is referenced by: eltrrels2 36620 trreleq 36623 eleqvrels2 36632 |
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