| Mathbox for Peter Mazsa |
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| Mirrors > Home > MPE Home > Th. List > Mathboxes > coideq | Structured version Visualization version GIF version | ||
| Description: Equality theorem for composition of two classes. (Contributed by Peter Mazsa, 23-Sep-2021.) |
| Ref | Expression |
|---|---|
| coideq | ⊢ (𝐴 = 𝐵 → (𝐴 ∘ 𝐴) = (𝐵 ∘ 𝐵)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | coeq1 5839 | . 2 ⊢ (𝐴 = 𝐵 → (𝐴 ∘ 𝐴) = (𝐵 ∘ 𝐴)) | |
| 2 | coeq2 5840 | . 2 ⊢ (𝐴 = 𝐵 → (𝐵 ∘ 𝐴) = (𝐵 ∘ 𝐵)) | |
| 3 | 1, 2 | eqtrd 2798 | 1 ⊢ (𝐴 = 𝐵 → (𝐴 ∘ 𝐴) = (𝐵 ∘ 𝐵)) |
| Colors of variables: wff setvar class |
| This proof depends on syntax axioms: → wi 4 = wceq 1569 ∘ ccom 5658 |
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1827 ax-4 1841 ax-5 1944 ax-6 2001 ax-7 2042 ax-8 2148 ax-9 2156 ax-ext 2735 |
| This proof depends on definitions: df-bi 210 df-an 402 df-ex 1812 df-sb 2101 df-clab 2742 df-cleq 2755 df-clel 2838 df-ss 3900 df-br 5106 df-opab 5170 df-co 5663 |
| This theorem is used by: eltrrels2 39735 trreleq 39738 eleqvrels2 39748 |
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