| Mathbox for Peter Mazsa |
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| Mirrors > Home > MPE Home > Th. List > Mathboxes > coideq | Structured version Visualization version GIF version | ||
| Description: Equality theorem for composition of two classes. (Contributed by Peter Mazsa, 23-Sep-2021.) |
| Ref | Expression |
|---|---|
| coideq | ⊢ (𝐴 = 𝐵 → (𝐴 ∘ 𝐴) = (𝐵 ∘ 𝐵)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | coeq1 5829 | . 2 ⊢ (𝐴 = 𝐵 → (𝐴 ∘ 𝐴) = (𝐵 ∘ 𝐴)) | |
| 2 | coeq2 5830 | . 2 ⊢ (𝐴 = 𝐵 → (𝐵 ∘ 𝐴) = (𝐵 ∘ 𝐵)) | |
| 3 | 1, 2 | eqtrd 2797 | 1 ⊢ (𝐴 = 𝐵 → (𝐴 ∘ 𝐴) = (𝐵 ∘ 𝐵)) |
| Colors of variables: wff setvar class |
| Syntax hints: → wi 4 = wceq 1560 ∘ ccom 5651 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1815 ax-4 1829 ax-5 1930 ax-6 1987 ax-7 2028 ax-8 2144 ax-9 2152 ax-ext 2734 |
| This theorem depends on definitions: df-bi 209 df-an 400 df-ex 1800 df-sb 2091 df-clab 2741 df-cleq 2754 df-clel 2837 df-ss 3921 df-br 5101 df-opab 5163 df-co 5656 |
| This theorem is referenced by: eltrrels2 39162 trreleq 39165 eleqvrels2 39175 |
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