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Theorem dferALTV2 39430
Description: Equivalence relation with natural domain predicate, see the comment of df-ers 39425. (Contributed by Peter Mazsa, 26-Jun-2021.) (Revised by Peter Mazsa, 30-Aug-2021.)
Assertion
Ref Expression
dferALTV2 (𝑅 ErALTV 𝐴 ↔ ( EqvRel 𝑅 ∧ (dom 𝑅 / 𝑅) = 𝐴))

Proof of Theorem dferALTV2
StepHypRef Expression
1 df-erALTV 39426 . 2 (𝑅 ErALTV 𝐴 ↔ ( EqvRel 𝑅𝑅 DomainQs 𝐴))
2 df-dmqs 39400 . . 3 (𝑅 DomainQs 𝐴 ↔ (dom 𝑅 / 𝑅) = 𝐴)
32anbi2i 634 . 2 (( EqvRel 𝑅𝑅 DomainQs 𝐴) ↔ ( EqvRel 𝑅 ∧ (dom 𝑅 / 𝑅) = 𝐴))
41, 3bitri 278 1 (𝑅 ErALTV 𝐴 ↔ ( EqvRel 𝑅 ∧ (dom 𝑅 / 𝑅) = 𝐴))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wb 209  wa 400   = wceq 1569  dom cdm 5660   / cqs 8691   EqvRel weqvrel 38877   DomainQs wdmqs 38884   ErALTV werALTV 38886
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 210  df-an 401  df-dmqs 39400  df-erALTV 39426
This theorem is used by:  erALTVeq1  39431  dfcomember2  39435  erimeq  39441  partim  39588  pet0  39595  petid  39597  petidres  39599  petinidres  39601  petxrnidres  39603  mainer  39625  petincnvepres  39640  pet  39642
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