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Theorem dferALTV2 39951
Description: Equivalence relation with natural domain predicate, see the comment of df-ers 39946. (Contributed by Peter Mazsa, 26-Jun-2021.) (Revised by Peter Mazsa, 30-Aug-2021.)
Assertion
Ref Expression
dferALTV2 (𝑅 ErALTV 𝐴 ↔ ( EqvRel 𝑅 ∧ (dom 𝑅 / 𝑅) = 𝐴))

Proof of Theorem dferALTV2
StepHypRef Expression
1 df-erALTV 39947 . 2 (𝑅 ErALTV 𝐴 ↔ ( EqvRel 𝑅 ∧ 𝑅 DomainQs 𝐴))
2 df-dmqs 39921 . . 3 (𝑅 DomainQs 𝐴 ↔ (dom 𝑅 / 𝑅) = 𝐴)
32anbi2i 635 . 2 (( EqvRel 𝑅 ∧ 𝑅 DomainQs 𝐴) ↔ ( EqvRel 𝑅 ∧ (dom 𝑅 / 𝑅) = 𝐴))
41, 3bitri 278 1 (𝑅 ErALTV 𝐴 ↔ ( EqvRel 𝑅 ∧ (dom 𝑅 / 𝑅) = 𝐴))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   ↔ wb 209   ∧ wa 401   = wceq 1570  dom cdm 5658   / cqs 8754   EqvRel weqvrel 39398   DomainQs wdmqs 39405   ErALTV werALTV 39407
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 210  df-an 402  df-dmqs 39921  df-erALTV 39947
This theorem is used by:  erALTVeq1  39952  dfcomember2  39956  erimeq  39962  partim  40109  pet0  40116  petid  40118  petidres  40120  petinidres  40122  petxrnidres  40124  mainer  40146  petincnvepres  40161  pet  40163
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