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Theorem dferALTV2 39462
Description: Equivalence relation with natural domain predicate, see the comment of df-ers 39457. (Contributed by Peter Mazsa, 26-Jun-2021.) (Revised by Peter Mazsa, 30-Aug-2021.)
Assertion
Ref Expression
dferALTV2 (𝑅 ErALTV 𝐴 ↔ ( EqvRel 𝑅 ∧ (dom 𝑅 / 𝑅) = 𝐴))

Proof of Theorem dferALTV2
StepHypRef Expression
1 df-erALTV 39458 . 2 (𝑅 ErALTV 𝐴 ↔ ( EqvRel 𝑅𝑅 DomainQs 𝐴))
2 df-dmqs 39432 . . 3 (𝑅 DomainQs 𝐴 ↔ (dom 𝑅 / 𝑅) = 𝐴)
32anbi2i 635 . 2 (( EqvRel 𝑅𝑅 DomainQs 𝐴) ↔ ( EqvRel 𝑅 ∧ (dom 𝑅 / 𝑅) = 𝐴))
41, 3bitri 278 1 (𝑅 ErALTV 𝐴 ↔ ( EqvRel 𝑅 ∧ (dom 𝑅 / 𝑅) = 𝐴))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wb 209  wa 401   = wceq 1570  dom cdm 5663   / cqs 8699   EqvRel weqvrel 38909   DomainQs wdmqs 38916   ErALTV werALTV 38918
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 210  df-an 402  df-dmqs 39432  df-erALTV 39458
This theorem is used by:  erALTVeq1  39463  dfcomember2  39467  erimeq  39473  partim  39620  pet0  39627  petid  39629  petidres  39631  petinidres  39633  petxrnidres  39635  mainer  39657  petincnvepres  39672  pet  39674
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