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Theorem dferALTV2 39120
Description: Equivalence relation with natural domain predicate, see the comment of df-ers 39115. (Contributed by Peter Mazsa, 26-Jun-2021.) (Revised by Peter Mazsa, 30-Aug-2021.)
Assertion
Ref Expression
dferALTV2 (𝑅 ErALTV 𝐴 ↔ ( EqvRel 𝑅 ∧ (dom 𝑅 / 𝑅) = 𝐴))

Proof of Theorem dferALTV2
StepHypRef Expression
1 df-erALTV 39116 . 2 (𝑅 ErALTV 𝐴 ↔ ( EqvRel 𝑅𝑅 DomainQs 𝐴))
2 df-dmqs 39090 . . 3 (𝑅 DomainQs 𝐴 ↔ (dom 𝑅 / 𝑅) = 𝐴)
32anbi2i 629 . 2 (( EqvRel 𝑅𝑅 DomainQs 𝐴) ↔ ( EqvRel 𝑅 ∧ (dom 𝑅 / 𝑅) = 𝐴))
41, 3bitri 276 1 (𝑅 ErALTV 𝐴 ↔ ( EqvRel 𝑅 ∧ (dom 𝑅 / 𝑅) = 𝐴))
Colors of variables: wff setvar class
Syntax hints:  wb 207  wa 396   = wceq 1547  dom cdm 5618   / cqs 8632   EqvRel weqvrel 38567   DomainQs wdmqs 38574   ErALTV werALTV 38576
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This theorem depends on definitions:  df-bi 208  df-an 397  df-dmqs 39090  df-erALTV 39116
This theorem is referenced by:  erALTVeq1  39121  dfcomember2  39125  erimeq  39131  partim  39278  pet0  39285  petid  39287  petidres  39289  petinidres  39291  petxrnidres  39293  mainer  39315  petincnvepres  39330  pet  39332
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