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Theorem ordi 1023
Description: Distributive law for disjunction. Theorem *4.41 of [WhiteheadRussell] p. 119. (Contributed by NM, 5-Jan-1993.) (Proof shortened by Andrew Salmon, 7-May-2011.) (Proof shortened by Wolf Lammen, 28-Nov-2013.)
Assertion
Ref Expression
ordi ((𝜑 ∨ (𝜓 ∧ 𝜒)) ↔ ((𝜑 ∨ 𝜓) ∧ (𝜑 ∨ 𝜒)))

Proof of Theorem ordi
StepHypRef Expression
1 jcab 527 . 2 ((¬ 𝜑 → (𝜓 ∧ 𝜒)) ↔ ((¬ 𝜑 → 𝜓) ∧ (¬ 𝜑 → 𝜒)))
2 df-or 862 . 2 ((𝜑 ∨ (𝜓 ∧ 𝜒)) ↔ (¬ 𝜑 → (𝜓 ∧ 𝜒)))
3 df-or 862 . . 3 ((𝜑 ∨ 𝜓) ↔ (¬ 𝜑 → 𝜓))
4 df-or 862 . . 3 ((𝜑 ∨ 𝜒) ↔ (¬ 𝜑 → 𝜒))
53, 4anbi12i 640 . 2 (((𝜑 ∨ 𝜓) ∧ (𝜑 ∨ 𝜒)) ↔ ((¬ 𝜑 → 𝜓) ∧ (¬ 𝜑 → 𝜒)))
61, 2, 53bitr4i 306 1 ((𝜑 ∨ (𝜓 ∧ 𝜒)) ↔ ((𝜑 ∨ 𝜓) ∧ (𝜑 ∨ 𝜒)))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  ¬ wn 3   → wi 4   ↔ wb 209   ∧ wa 401   ∨ wo 861
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862
This theorem is used by:  ordir  1024  orddi  1027  pm5.63  1037  pm4.43  1040  cadan  1642  undi  4231  undif3  4246  undif4  4420  poxp2  8153  elnn1uz2  13045  or3di  33050  wl-df3-3mintru2  38389  ifpan23  44445  ifpidg  44476  ifpim123g  44485
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