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| Mirrors > Home > MPE Home > Th. List > rextp | Structured version Visualization version GIF version | ||
| Description: Convert an existential quantification over an unordered triple to a disjunction. (Contributed by Mario Carneiro, 23-Apr-2015.) |
| Ref | Expression |
|---|---|
| raltp.1 | ⊢ 𝐴 ∈ V |
| raltp.2 | ⊢ 𝐵 ∈ V |
| raltp.3 | ⊢ 𝐶 ∈ V |
| raltp.4 | ⊢ (𝑥 = 𝐴 → (𝜑 ↔ 𝜓)) |
| raltp.5 | ⊢ (𝑥 = 𝐵 → (𝜑 ↔ 𝜒)) |
| raltp.6 | ⊢ (𝑥 = 𝐶 → (𝜑 ↔ 𝜃)) |
| Ref | Expression |
|---|---|
| rextp | ⊢ (∃𝑥 ∈ {𝐴, 𝐵, 𝐶}𝜑 ↔ (𝜓 ∨ 𝜒 ∨ 𝜃)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | raltp.1 | . 2 ⊢ 𝐴 ∈ V | |
| 2 | raltp.2 | . 2 ⊢ 𝐵 ∈ V | |
| 3 | raltp.3 | . 2 ⊢ 𝐶 ∈ V | |
| 4 | raltp.4 | . . 3 ⊢ (𝑥 = 𝐴 → (𝜑 ↔ 𝜓)) | |
| 5 | raltp.5 | . . 3 ⊢ (𝑥 = 𝐵 → (𝜑 ↔ 𝜒)) | |
| 6 | raltp.6 | . . 3 ⊢ (𝑥 = 𝐶 → (𝜑 ↔ 𝜃)) | |
| 7 | 4, 5, 6 | rextpg 4657 | . 2 ⊢ ((𝐴 ∈ V ∧ 𝐵 ∈ V ∧ 𝐶 ∈ V) → (∃𝑥 ∈ {𝐴, 𝐵, 𝐶}𝜑 ↔ (𝜓 ∨ 𝜒 ∨ 𝜃))) |
| 8 | 1, 2, 3, 7 | mp3an 1481 | 1 ⊢ (∃𝑥 ∈ {𝐴, 𝐵, 𝐶}𝜑 ↔ (𝜓 ∨ 𝜒 ∨ 𝜃)) |
| Colors of variables: wff setvar class |
| Syntax hints: → wi 4 ↔ wb 208 ∨ w3o 1096 = wceq 1559 ∈ wcel 2141 ∃wrex 3085 Vcvv 3453 {ctp 4585 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1814 ax-4 1828 ax-5 1929 ax-6 1986 ax-7 2027 ax-8 2143 ax-9 2151 ax-ext 2733 |
| This theorem depends on definitions: df-bi 209 df-an 400 df-or 859 df-3or 1098 df-3an 1099 df-tru 1562 df-ex 1799 df-sb 2090 df-clab 2740 df-cleq 2753 df-clel 2836 df-ral 3076 df-rex 3086 df-v 3455 df-un 3909 df-sn 4582 df-pr 4584 df-tp 4586 |
| This theorem is referenced by: 1cubr 26884 |
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