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Theorem sbc3ie 3815
Description: Conversion of implicit substitution to explicit class substitution. (Contributed by Mario Carneiro, 19-Jun-2014.) (Revised by Mario Carneiro, 29-Dec-2014.)
Hypotheses
Ref Expression
sbc3ie.1 𝐴 ∈ V
sbc3ie.2 𝐵 ∈ V
sbc3ie.3 𝐶 ∈ V
sbc3ie.4 ((𝑥 = 𝐴 ∧ 𝑦 = 𝐵 ∧ 𝑧 = 𝐶) → (𝜑 ↔ 𝜓))
Assertion
Ref Expression
sbc3ie ([𝐴 / 𝑥][𝐵 / 𝑦][𝐶 / 𝑧]𝜑 ↔ 𝜓)
Distinct variable groups:   𝑥,𝑦,𝑧,𝐴   𝑦,𝐵,𝑧   𝑧,𝐶   𝜓,𝑥,𝑦,𝑧
Allowed substitution hints:   𝜑(𝑥, 𝑦, 𝑧)   𝐵(𝑥)   𝐶(𝑥, 𝑦)

Proof of Theorem sbc3ie
StepHypRef Expression
1 sbc3ie.1 . 2 𝐴 ∈ V
2 sbc3ie.2 . 2 𝐵 ∈ V
3 sbc3ie.3 . . . 4 𝐶 ∈ V
43a1i 11 . . 3 ((𝑥 = 𝐴 ∧ 𝑦 = 𝐵) → 𝐶 ∈ V)
5 sbc3ie.4 . . . 4 ((𝑥 = 𝐴 ∧ 𝑦 = 𝐵 ∧ 𝑧 = 𝐶) → (𝜑 ↔ 𝜓))
653expa 1136 . . 3 (((𝑥 = 𝐴 ∧ 𝑦 = 𝐵) ∧ 𝑧 = 𝐶) → (𝜑 ↔ 𝜓))
74, 6sbcied 3781 . 2 ((𝑥 = 𝐴 ∧ 𝑦 = 𝐵) → ([𝐶 / 𝑧]𝜑 ↔ 𝜓))
81, 2, 7sbc2ie 3813 1 ([𝐴 / 𝑥][𝐵 / 𝑦][𝐶 / 𝑧]𝜑 ↔ 𝜓)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ↔ wb 209   ∧ wa 401   ∧ w3a 1103   = wceq 1569   ∈ wcel 2144  Vcvv 3450  [wsbc 3738
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-ext 2732
This proof depends on definitions:  df-bi 210  df-an 402  df-3an 1105  df-tru 1572  df-ex 1812  df-sb 2099  df-clab 2739  df-cleq 2752  df-clel 2835  df-sbc 3739
This theorem is used by:  isdlat  18701  islmod  21144  isslmd  33809  hdmap1fval  42946  hdmapfval  42977  hgmapfval  43036  rmydioph  44114
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