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Theorem sbv 2121
Description: Substitution for a variable not occurring in a proposition. See sbf 2305 for a version without disjoint variable condition on 𝑥, 𝜑. If one adds a disjoint variable condition on 𝑥, 𝑡, then sbv 2121 can be proved directly by chaining equsv 2032 with sb6 2118. (Contributed by BJ, 22-Dec-2020.)
Assertion
Ref Expression
sbv ([𝑡 / 𝑥]𝜑𝜑)
Distinct variable group:   𝜑,𝑥
Allowed substitution hint:   𝜑(𝑡)

Proof of Theorem sbv
StepHypRef Expression
1 spsbe 2115 . . 3 ([𝑡 / 𝑥]𝜑 → ∃𝑥𝜑)
2 ax5e 1941 . . 3 (∃𝑥𝜑𝜑)
31, 2syl 18 . 2 ([𝑡 / 𝑥]𝜑𝜑)
4 ax-5 1939 . . 3 (𝜑 → ∀𝑥𝜑)
5 stdpc4 2101 . . 3 (∀𝑥𝜑 → [𝑡 / 𝑥]𝜑)
64, 5syl 18 . 2 (𝜑 → [𝑡 / 𝑥]𝜑)
73, 6impbii 212 1 ([𝑡 / 𝑥]𝜑𝜑)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wb 209  wal 1567  wex 1808  [wsb 2095
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1824  ax-4 1838  ax-5 1939  ax-6 1996  ax-7 2037
This proof depends on definitions:  df-bi 210  df-an 401  df-ex 1809  df-sb 2096
This theorem is used by:  sbcom4  2122  sbrimvw  2124  sbievw  2127  sbievw2  2132  sbabel  2956  sbcg  3815  ab0w  4334  iuninc  32916  measiuns  34616  ballotlemodife  34897  xpab  36226  subsym1  36966  bj-vn0ALT  37736  mptsnunlem  38012  ichv  48226  ichf  48227
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