Theorem seeq12d 5627

Description: Equality deduction for the set-like predicate. (Contributed by Matthew House, 10-Sep-2025.)

Hypotheses

Ref	Expression
seeq12d.1	⊢ (𝜑 → 𝑅 = 𝑆)
seeq12d.2	⊢ (𝜑 → 𝐴 = 𝐵)

Assertion

Ref	Expression
seeq12d	⊢ (𝜑 → (𝑅 Se 𝐴 ↔ 𝑆 Se 𝐵))

Proof of Theorem seeq12d

Step	Hyp	Ref	Expression
1		seeq12d.1	. 2 ⊢ (𝜑 → 𝑅 = 𝑆)
2		seeq12d.2	. 2 ⊢ (𝜑 → 𝐴 = 𝐵)
3		seeq1 5625	. . 3 ⊢ (𝑅 = 𝑆 → (𝑅 Se 𝐴 ↔ 𝑆 Se 𝐴))
4		seeq2 5626	. . 3 ⊢ (𝐴 = 𝐵 → (𝑆 Se 𝐴 ↔ 𝑆 Se 𝐵))
5	3, 4	sylan9bb 519	. 2 ⊢ ((𝑅 = 𝑆 ∧ 𝐴 = 𝐵) → (𝑅 Se 𝐴 ↔ 𝑆 Se 𝐵))
6	1, 2, 5	syl2anc 596	1 ⊢ (𝜑 → (𝑅 Se 𝐴 ↔ 𝑆 Se 𝐵))

This proof depends on syntax axioms:   → wi 4   ↔ wb 209   = wceq 1570   Se wse 5606

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043  ax-8 2149  ax-9 2157  ax-ext 2735  ax-sep 5252

This proof depends on definitions:  df-bi 210  df-an 402  df-3an 1105  df-tru 1573  df-ex 1813  df-sb 2102  df-clab 2742  df-cleq 2755  df-clel 2839  df-ral 3081  df-rab 3417  df-v 3456  df-ss 3901  df-in 4094  df-br 5107  df-se 5609

This theorem is used by: (None)