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Theorem wl-df3maxtru1 35761
Description: Assuming "(n+1)-maxtru1" ↔ ¬ "(n+1)-mintru-2", we can deduce from the recursion formula given in wl-df-3mintru2 35753, that a similiar one

"(n+1)-maxtru1" ↔ if-(𝜑,-. "n-mintru-1" , "n-maxtru1" )

is valid for expressing 'at most one input is true'. This can also be rephrased as a mutual exclusivity of propositional expressions (no two of a sequence of inputs can simultaniously be true). Of course, this suggests that all inputs depend on variables 𝜂, 𝜁... Whatever wellformed expression we plugin for these variables, it will render at most one of the inputs true.

The here introduced mutual exclusivity is possibly useful for case studies, where we want the cases be sort of 'disjoint'. One can further imagine that a complete case scenario demands that the 'at most' is sharpened to 'exactly one'. This does not impose any difficulty here, as one of the inputs will then be the negation of all others be or'ed. As one input is determined, 'at most one' is sufficient to describe the general form here.

Since cadd is an alias for 'at least 2 out of three are true', its negation is under focus here. (Contributed by Wolf Lammen, 23-Jun-2024.)

Assertion
Ref Expression
wl-df3maxtru1 (¬ cadd(𝜑, 𝜓, 𝜒) ↔ if-(𝜑, (𝜓 𝜒), (𝜓𝜒)))

Proof of Theorem wl-df3maxtru1
StepHypRef Expression
1 cadnot 1615 . 2 (¬ cadd(𝜑, 𝜓, 𝜒) ↔ cadd(¬ 𝜑, ¬ 𝜓, ¬ 𝜒))
2 wl-df-3mintru2 35753 . 2 (cadd(¬ 𝜑, ¬ 𝜓, ¬ 𝜒) ↔ if-(¬ 𝜑, (¬ 𝜓 ∨ ¬ 𝜒), (¬ 𝜓 ∧ ¬ 𝜒)))
3 ifpn 1071 . . 3 (if-(𝜑, (𝜓 𝜒), (𝜓𝜒)) ↔ if-(¬ 𝜑, (𝜓𝜒), (𝜓 𝜒)))
4 nanor 1492 . . . . . 6 ((𝜓𝜒) ↔ (¬ 𝜓 ∨ ¬ 𝜒))
54a1i 11 . . . . 5 (⊤ → ((𝜓𝜒) ↔ (¬ 𝜓 ∨ ¬ 𝜒)))
6 df-nor 1528 . . . . . . 7 ((𝜓 𝜒) ↔ ¬ (𝜓𝜒))
7 ioran 981 . . . . . . 7 (¬ (𝜓𝜒) ↔ (¬ 𝜓 ∧ ¬ 𝜒))
86, 7bitri 274 . . . . . 6 ((𝜓 𝜒) ↔ (¬ 𝜓 ∧ ¬ 𝜒))
98a1i 11 . . . . 5 (⊤ → ((𝜓 𝜒) ↔ (¬ 𝜓 ∧ ¬ 𝜒)))
105, 9ifpbi23d 1079 . . . 4 (⊤ → (if-(¬ 𝜑, (𝜓𝜒), (𝜓 𝜒)) ↔ if-(¬ 𝜑, (¬ 𝜓 ∨ ¬ 𝜒), (¬ 𝜓 ∧ ¬ 𝜒))))
1110mptru 1547 . . 3 (if-(¬ 𝜑, (𝜓𝜒), (𝜓 𝜒)) ↔ if-(¬ 𝜑, (¬ 𝜓 ∨ ¬ 𝜒), (¬ 𝜓 ∧ ¬ 𝜒)))
123, 11bitr2i 275 . 2 (if-(¬ 𝜑, (¬ 𝜓 ∨ ¬ 𝜒), (¬ 𝜓 ∧ ¬ 𝜒)) ↔ if-(𝜑, (𝜓 𝜒), (𝜓𝜒)))
131, 2, 123bitri 296 1 (¬ cadd(𝜑, 𝜓, 𝜒) ↔ if-(𝜑, (𝜓 𝜒), (𝜓𝜒)))
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wb 205  wa 396  wo 844  if-wif 1060  wnan 1488   wnor 1527  wtru 1541  caddwcad 1606
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This theorem depends on definitions:  df-bi 206  df-an 397  df-or 845  df-ifp 1061  df-3or 1087  df-3an 1088  df-nan 1489  df-xor 1509  df-nor 1528  df-tru 1543  df-cad 1607
This theorem is referenced by: (None)
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