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Theorem wl-df3maxtru1 37947
Description: Assuming "(n+1)-maxtru1" ↔ ¬ "(n+1)-mintru-2", we can deduce from the recursion formula given in wl-df-3mintru2 37939, that a similiar one

"(n+1)-maxtru1" ↔ if-(𝜑,-. "n-mintru-1" , "n-maxtru1" )

is valid for expressing 'at most one input is true'. This can also be rephrased as a mutual exclusivity of propositional expressions (no two of a sequence of inputs can simultaneously be true). Of course, this suggests that all inputs depend on variables 𝜂, 𝜁... Whatever wellformed expression we plugin for these variables, it will render at most one of the inputs true.

The here introduced mutual exclusivity is possibly useful for case studies, where we want the cases be sort of 'disjoint'. One can further imagine that a complete case scenario demands that the 'at most' is sharpened to 'exactly one'. This does not impose any difficulty here, as one of the inputs will then be the negation of all others be or'ed. As one input is determined, 'at most one' is sufficient to describe the general form here.

Since cadd is an alias for 'at least 2 out of three are true', its negation is under focus here. (Contributed by Wolf Lammen, 23-Jun-2024.)

Assertion
Ref Expression
wl-df3maxtru1 (¬ cadd(𝜑, 𝜓, 𝜒) ↔ if-(𝜑, (𝜓 𝜒), (𝜓𝜒)))

Proof of Theorem wl-df3maxtru1
StepHypRef Expression
1 cadnot 1634 . 2 (¬ cadd(𝜑, 𝜓, 𝜒) ↔ cadd(¬ 𝜑, ¬ 𝜓, ¬ 𝜒))
2 wl-df-3mintru2 37939 . 2 (cadd(¬ 𝜑, ¬ 𝜓, ¬ 𝜒) ↔ if-(¬ 𝜑, (¬ 𝜓 ∨ ¬ 𝜒), (¬ 𝜓 ∧ ¬ 𝜒)))
3 ifpn 1084 . . 3 (if-(𝜑, (𝜓 𝜒), (𝜓𝜒)) ↔ if-(¬ 𝜑, (𝜓𝜒), (𝜓 𝜒)))
4 nanor 1514 . . . . . 6 ((𝜓𝜒) ↔ (¬ 𝜓 ∨ ¬ 𝜒))
54a1i 11 . . . . 5 (⊤ → ((𝜓𝜒) ↔ (¬ 𝜓 ∨ ¬ 𝜒)))
6 df-nor 1548 . . . . . . 7 ((𝜓 𝜒) ↔ ¬ (𝜓𝜒))
7 ioran 996 . . . . . . 7 (¬ (𝜓𝜒) ↔ (¬ 𝜓 ∧ ¬ 𝜒))
86, 7bitri 277 . . . . . 6 ((𝜓 𝜒) ↔ (¬ 𝜓 ∧ ¬ 𝜒))
98a1i 11 . . . . 5 (⊤ → ((𝜓 𝜒) ↔ (¬ 𝜓 ∧ ¬ 𝜒)))
105, 9ifpbi23d 1090 . . . 4 (⊤ → (if-(¬ 𝜑, (𝜓𝜒), (𝜓 𝜒)) ↔ if-(¬ 𝜑, (¬ 𝜓 ∨ ¬ 𝜒), (¬ 𝜓 ∧ ¬ 𝜒))))
1110mptru 1566 . . 3 (if-(¬ 𝜑, (𝜓𝜒), (𝜓 𝜒)) ↔ if-(¬ 𝜑, (¬ 𝜓 ∨ ¬ 𝜒), (¬ 𝜓 ∧ ¬ 𝜒)))
123, 11bitr2i 278 . 2 (if-(¬ 𝜑, (¬ 𝜓 ∨ ¬ 𝜒), (¬ 𝜓 ∧ ¬ 𝜒)) ↔ if-(𝜑, (𝜓 𝜒), (𝜓𝜒)))
131, 2, 123bitri 299 1 (¬ cadd(𝜑, 𝜓, 𝜒) ↔ if-(𝜑, (𝜓 𝜒), (𝜓𝜒)))
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wb 208  wa 399  wo 858  if-wif 1073  wnan 1510   wnor 1547  wtru 1560  caddwcad 1625
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This theorem depends on definitions:  df-bi 209  df-an 400  df-or 859  df-ifp 1074  df-3or 1098  df-3an 1099  df-nan 1511  df-xor 1531  df-nor 1548  df-tru 1562  df-cad 1626
This theorem is referenced by: (None)
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