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Theorem nfnf1 1590
Description: 𝑥 is not free in 𝑥𝜑. (Contributed by Mario Carneiro, 11-Aug-2016.)
Assertion
Ref Expression
nfnf1 𝑥𝑥𝜑

Proof of Theorem nfnf1
StepHypRef Expression
1 df-nf 1507 . 2 (Ⅎ𝑥𝜑 ↔ ∀𝑥(𝜑 → ∀𝑥𝜑))
2 nfa1 1587 . 2 𝑥𝑥(𝜑 → ∀𝑥𝜑)
31, 2nfxfr 1520 1 𝑥𝑥𝜑
Colors of variables: wff set class
Syntax hints:  wi 4  wal 1393  wnf 1506
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1493  ax-gen 1495  ax-ial 1580
This theorem depends on definitions:  df-bi 117  df-nf 1507
This theorem is referenced by:  nfimd  1631  nfnt  1702  nfald  1806  equs5or  1876  sbcomxyyz  2023  nfsb4t  2065  nfnfc1  2375  nfabdw  2391  sbcnestgf  3176  dfnfc2  3905  bdsepnft  16208  setindft  16286  strcollnft  16305
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