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Theorem nfnf1 1566
Description: 𝑥 is not free in 𝑥𝜑. (Contributed by Mario Carneiro, 11-Aug-2016.)
Assertion
Ref Expression
nfnf1 𝑥𝑥𝜑

Proof of Theorem nfnf1
StepHypRef Expression
1 df-nf 1483 . 2 (Ⅎ𝑥𝜑 ↔ ∀𝑥(𝜑 → ∀𝑥𝜑))
2 nfa1 1563 . 2 𝑥𝑥(𝜑 → ∀𝑥𝜑)
31, 2nfxfr 1496 1 𝑥𝑥𝜑
Colors of variables: wff set class
Syntax hints:  wi 4  wal 1370  wnf 1482
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1469  ax-gen 1471  ax-ial 1556
This theorem depends on definitions:  df-bi 117  df-nf 1483
This theorem is referenced by:  nfimd  1607  nfnt  1678  nfald  1782  equs5or  1852  sbcomxyyz  1999  nfsb4t  2041  nfnfc1  2350  nfabdw  2366  sbcnestgf  3144  dfnfc2  3867  bdsepnft  15785  setindft  15863  strcollnft  15882
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