Theorem sqxpeqd 4651

Description: Equality deduction for a Cartesian square, see Wikipedia "Cartesian product", https://en.wikipedia.org/wiki/Cartesian_product#n-ary_Cartesian_power. (Contributed by AV, 13-Jan-2020.)

Hypothesis

Ref	Expression
xpeq1d.1	|- ( ph -> A = B )

Assertion

Ref	Expression
sqxpeqd	|- ( ph -> ( A X. A ) = ( B X. B ) )

Proof of Theorem sqxpeqd

Step	Hyp	Ref	Expression
1		xpeq1d.1	. 2 |- ( ph -> A = B )
2	1, 1	xpeq12d 4650	1 |- ( ph -> ( A X. A ) = ( B X. B ) )

Syntax hints:   -> wi 4   = wceq 1353   X. cxp 4623

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1447  ax-7 1448  ax-gen 1449  ax-ie1 1493  ax-ie2 1494  ax-8 1504  ax-11 1506  ax-4 1510  ax-17 1526  ax-i9 1530  ax-ial 1534  ax-i5r 1535  ax-ext 2159

This theorem depends on definitions:  df-bi 117  df-tru 1356  df-nf 1461  df-sb 1763  df-clab 2164  df-cleq 2170  df-clel 2173  df-opab 4064  df-xp 4631

This theorem is referenced by:  intopsn  12718  srg1zr  13101  ispsmet  13694  isxms  13822  isms  13824  xmspropd  13848  mspropd  13849