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Theorem sqxpeqd 4635
Description: Equality deduction for a Cartesian square, see Wikipedia "Cartesian product", https://en.wikipedia.org/wiki/Cartesian_product#n-ary_Cartesian_power. (Contributed by AV, 13-Jan-2020.)
Hypothesis
Ref Expression
xpeq1d.1 (𝜑𝐴 = 𝐵)
Assertion
Ref Expression
sqxpeqd (𝜑 → (𝐴 × 𝐴) = (𝐵 × 𝐵))

Proof of Theorem sqxpeqd
StepHypRef Expression
1 xpeq1d.1 . 2 (𝜑𝐴 = 𝐵)
21, 1xpeq12d 4634 1 (𝜑 → (𝐴 × 𝐴) = (𝐵 × 𝐵))
Colors of variables: wff set class
Syntax hints:  wi 4   = wceq 1348   × cxp 4607
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1440  ax-7 1441  ax-gen 1442  ax-ie1 1486  ax-ie2 1487  ax-8 1497  ax-11 1499  ax-4 1503  ax-17 1519  ax-i9 1523  ax-ial 1527  ax-i5r 1528  ax-ext 2152
This theorem depends on definitions:  df-bi 116  df-tru 1351  df-nf 1454  df-sb 1756  df-clab 2157  df-cleq 2163  df-clel 2166  df-opab 4049  df-xp 4615
This theorem is referenced by:  intopsn  12614  ispsmet  13082  isxms  13210  isms  13212  xmspropd  13236  mspropd  13237
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