Theorem difssd 3150

Description: A difference of two classes is contained in the minuend. Deduction form of difss 3149. (Contributed by David Moews, 1-May-2017.)

Assertion

Ref	Expression
difssd	⊢ (𝜑 → (𝐴 ∖ 𝐵) ⊆ 𝐴)

Proof of Theorem difssd

Step	Hyp	Ref	Expression
1		difss 3149	. 2 ⊢ (𝐴 ∖ 𝐵) ⊆ 𝐴
2	1	a1i 9	1 ⊢ (𝜑 → (𝐴 ∖ 𝐵) ⊆ 𝐴)

Syntax hints:   → wi 4   ∖ cdif 3018   ⊆ wss 3021

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-in1 584  ax-in2 585  ax-io 671  ax-5 1391  ax-7 1392  ax-gen 1393  ax-ie1 1437  ax-ie2 1438  ax-8 1450  ax-10 1451  ax-11 1452  ax-i12 1453  ax-bndl 1454  ax-4 1455  ax-17 1474  ax-i9 1478  ax-ial 1482  ax-i5r 1483  ax-ext 2082

This theorem depends on definitions:  df-bi 116  df-tru 1302  df-nf 1405  df-sb 1704  df-clab 2087  df-cleq 2093  df-clel 2096  df-nfc 2229  df-v 2643  df-dif 3023  df-in 3027  df-ss 3034

This theorem is referenced by: (None)