Theorem difssd 3116

Description: A difference of two classes is contained in the minuend. Deduction form of difss 3115. (Contributed by David Moews, 1-May-2017.)

Assertion

Ref	Expression
difssd	⊢ (𝜑 → (𝐴 ∖ 𝐵) ⊆ 𝐴)

Proof of Theorem difssd

Step	Hyp	Ref	Expression
1		difss 3115	. 2 ⊢ (𝐴 ∖ 𝐵) ⊆ 𝐴
2	1	a1i 9	1 ⊢ (𝜑 → (𝐴 ∖ 𝐵) ⊆ 𝐴)

Syntax hints:   → wi 4   ∖ cdif 2985   ⊆ wss 2988

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-in1 577  ax-in2 578  ax-io 663  ax-5 1379  ax-7 1380  ax-gen 1381  ax-ie1 1425  ax-ie2 1426  ax-8 1438  ax-10 1439  ax-11 1440  ax-i12 1441  ax-bndl 1442  ax-4 1443  ax-17 1462  ax-i9 1466  ax-ial 1470  ax-i5r 1471  ax-ext 2067

This theorem depends on definitions:  df-bi 115  df-tru 1290  df-nf 1393  df-sb 1690  df-clab 2072  df-cleq 2078  df-clel 2081  df-nfc 2214  df-v 2617  df-dif 2990  df-in 2994  df-ss 3001

This theorem is referenced by: (None)