Theorem difssd 3299

Description: A difference of two classes is contained in the minuend. Deduction form of difss 3298. (Contributed by David Moews, 1-May-2017.)

Assertion

Ref	Expression
difssd	⊢ (𝜑 → (𝐴 ∖ 𝐵) ⊆ 𝐴)

Proof of Theorem difssd

Step	Hyp	Ref	Expression
1		difss 3298	. 2 ⊢ (𝐴 ∖ 𝐵) ⊆ 𝐴
2	1	a1i 9	1 ⊢ (𝜑 → (𝐴 ∖ 𝐵) ⊆ 𝐴)

Syntax hints:   → wi 4   ∖ cdif 3162   ⊆ wss 3165

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 615  ax-in2 616  ax-io 710  ax-5 1469  ax-7 1470  ax-gen 1471  ax-ie1 1515  ax-ie2 1516  ax-8 1526  ax-10 1527  ax-11 1528  ax-i12 1529  ax-bndl 1531  ax-4 1532  ax-17 1548  ax-i9 1552  ax-ial 1556  ax-i5r 1557  ax-ext 2186

This theorem depends on definitions:  df-bi 117  df-tru 1375  df-nf 1483  df-sb 1785  df-clab 2191  df-cleq 2197  df-clel 2200  df-nfc 2336  df-v 2773  df-dif 3167  df-in 3171  df-ss 3178

This theorem is referenced by:  bj-charfun  15705  bj-charfundc  15706