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Theorem elsuc2 4297
Description: Membership in a successor. (Contributed by NM, 15-Sep-2003.)
Hypothesis
Ref Expression
elsuc.1 𝐴 ∈ V
Assertion
Ref Expression
elsuc2 (𝐵 ∈ suc 𝐴 ↔ (𝐵𝐴𝐵 = 𝐴))

Proof of Theorem elsuc2
StepHypRef Expression
1 elsuc.1 . 2 𝐴 ∈ V
2 elsuc2g 4295 . 2 (𝐴 ∈ V → (𝐵 ∈ suc 𝐴 ↔ (𝐵𝐴𝐵 = 𝐴)))
31, 2ax-mp 5 1 (𝐵 ∈ suc 𝐴 ↔ (𝐵𝐴𝐵 = 𝐴))
Colors of variables: wff set class
Syntax hints:  wb 104  wo 680   = wceq 1314  wcel 1463  Vcvv 2658  suc csuc 4255
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-io 681  ax-5 1406  ax-7 1407  ax-gen 1408  ax-ie1 1452  ax-ie2 1453  ax-8 1465  ax-10 1466  ax-11 1467  ax-i12 1468  ax-bndl 1469  ax-4 1470  ax-17 1489  ax-i9 1493  ax-ial 1497  ax-i5r 1498  ax-ext 2097
This theorem depends on definitions:  df-bi 116  df-tru 1317  df-nf 1420  df-sb 1719  df-clab 2102  df-cleq 2108  df-clel 2111  df-nfc 2245  df-v 2660  df-un 3043  df-sn 3501  df-suc 4261
This theorem is referenced by:  nnsucelsuc  6353
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