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Theorem eqtr2 2158
Description: A transitive law for class equality. (Contributed by NM, 20-May-2005.) (Proof shortened by Andrew Salmon, 25-May-2011.)
Assertion
Ref Expression
eqtr2 ((𝐴 = 𝐵𝐴 = 𝐶) → 𝐵 = 𝐶)

Proof of Theorem eqtr2
StepHypRef Expression
1 eqcom 2141 . 2 (𝐴 = 𝐵𝐵 = 𝐴)
2 eqtr 2157 . 2 ((𝐵 = 𝐴𝐴 = 𝐶) → 𝐵 = 𝐶)
31, 2sylanb 282 1 ((𝐴 = 𝐵𝐴 = 𝐶) → 𝐵 = 𝐶)
Colors of variables: wff set class
Syntax hints:  wi 4  wa 103   = wceq 1331
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1423  ax-gen 1425  ax-4 1487  ax-17 1506  ax-ext 2121
This theorem depends on definitions:  df-bi 116  df-cleq 2132
This theorem is referenced by:  eqvinc  2808  eqvincg  2809  moop2  4173  reusv3i  4380  relop  4689  f0rn0  5317  fliftfun  5697  th3qlem1  6531  enq0ref  7248  enq0tr  7249  genpdisj  7338  addlsub  8139  fsum2dlemstep  11210  0dvds  11519  cncongr1  11790
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