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Theorem eqtr2 2196
Description: A transitive law for class equality. (Contributed by NM, 20-May-2005.) (Proof shortened by Andrew Salmon, 25-May-2011.)
Assertion
Ref Expression
eqtr2 ((𝐴 = 𝐵𝐴 = 𝐶) → 𝐵 = 𝐶)

Proof of Theorem eqtr2
StepHypRef Expression
1 eqcom 2179 . 2 (𝐴 = 𝐵𝐵 = 𝐴)
2 eqtr 2195 . 2 ((𝐵 = 𝐴𝐴 = 𝐶) → 𝐵 = 𝐶)
31, 2sylanb 284 1 ((𝐴 = 𝐵𝐴 = 𝐶) → 𝐵 = 𝐶)
Colors of variables: wff set class
Syntax hints:  wi 4  wa 104   = wceq 1353
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1447  ax-gen 1449  ax-4 1510  ax-17 1526  ax-ext 2159
This theorem depends on definitions:  df-bi 117  df-cleq 2170
This theorem is referenced by:  eqvinc  2860  eqvincg  2861  moop2  4249  reusv3i  4457  relop  4774  f0rn0  5407  fliftfun  5792  th3qlem1  6632  enq0ref  7427  enq0tr  7428  genpdisj  7517  addlsub  8321  fsum2dlemstep  11433  0dvds  11809  cncongr1  12093
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