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Mirrors > Home > ILE Home > Th. List > eqtr2 | GIF version |
Description: A transitive law for class equality. (Contributed by NM, 20-May-2005.) (Proof shortened by Andrew Salmon, 25-May-2011.) |
Ref | Expression |
---|---|
eqtr2 | ⊢ ((𝐴 = 𝐵 ∧ 𝐴 = 𝐶) → 𝐵 = 𝐶) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | eqcom 2177 | . 2 ⊢ (𝐴 = 𝐵 ↔ 𝐵 = 𝐴) | |
2 | eqtr 2193 | . 2 ⊢ ((𝐵 = 𝐴 ∧ 𝐴 = 𝐶) → 𝐵 = 𝐶) | |
3 | 1, 2 | sylanb 284 | 1 ⊢ ((𝐴 = 𝐵 ∧ 𝐴 = 𝐶) → 𝐵 = 𝐶) |
Colors of variables: wff set class |
Syntax hints: → wi 4 ∧ wa 104 = wceq 1353 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-5 1445 ax-gen 1447 ax-4 1508 ax-17 1524 ax-ext 2157 |
This theorem depends on definitions: df-bi 117 df-cleq 2168 |
This theorem is referenced by: eqvinc 2858 eqvincg 2859 moop2 4245 reusv3i 4453 relop 4770 f0rn0 5402 fliftfun 5787 th3qlem1 6627 enq0ref 7407 enq0tr 7408 genpdisj 7497 addlsub 8301 fsum2dlemstep 11408 0dvds 11784 cncongr1 12068 |
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