ILE Home Intuitionistic Logic Explorer < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  ILE Home  >  Th. List  >  eqtr2 GIF version

Theorem eqtr2 2194
Description: A transitive law for class equality. (Contributed by NM, 20-May-2005.) (Proof shortened by Andrew Salmon, 25-May-2011.)
Assertion
Ref Expression
eqtr2 ((𝐴 = 𝐵𝐴 = 𝐶) → 𝐵 = 𝐶)

Proof of Theorem eqtr2
StepHypRef Expression
1 eqcom 2177 . 2 (𝐴 = 𝐵𝐵 = 𝐴)
2 eqtr 2193 . 2 ((𝐵 = 𝐴𝐴 = 𝐶) → 𝐵 = 𝐶)
31, 2sylanb 284 1 ((𝐴 = 𝐵𝐴 = 𝐶) → 𝐵 = 𝐶)
Colors of variables: wff set class
Syntax hints:  wi 4  wa 104   = wceq 1353
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1445  ax-gen 1447  ax-4 1508  ax-17 1524  ax-ext 2157
This theorem depends on definitions:  df-bi 117  df-cleq 2168
This theorem is referenced by:  eqvinc  2858  eqvincg  2859  moop2  4245  reusv3i  4453  relop  4770  f0rn0  5402  fliftfun  5787  th3qlem1  6627  enq0ref  7407  enq0tr  7408  genpdisj  7497  addlsub  8301  fsum2dlemstep  11408  0dvds  11784  cncongr1  12068
  Copyright terms: Public domain W3C validator