ILE Home Intuitionistic Logic Explorer < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  ILE Home  >  Th. List  >  eqtr2 GIF version

Theorem eqtr2 2159
Description: A transitive law for class equality. (Contributed by NM, 20-May-2005.) (Proof shortened by Andrew Salmon, 25-May-2011.)
Assertion
Ref Expression
eqtr2 ((𝐴 = 𝐵𝐴 = 𝐶) → 𝐵 = 𝐶)

Proof of Theorem eqtr2
StepHypRef Expression
1 eqcom 2142 . 2 (𝐴 = 𝐵𝐵 = 𝐴)
2 eqtr 2158 . 2 ((𝐵 = 𝐴𝐴 = 𝐶) → 𝐵 = 𝐶)
31, 2sylanb 282 1 ((𝐴 = 𝐵𝐴 = 𝐶) → 𝐵 = 𝐶)
Colors of variables: wff set class
Syntax hints:  wi 4  wa 103   = wceq 1332
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1424  ax-gen 1426  ax-4 1488  ax-17 1507  ax-ext 2122
This theorem depends on definitions:  df-bi 116  df-cleq 2133
This theorem is referenced by:  eqvinc  2812  eqvincg  2813  moop2  4181  reusv3i  4388  relop  4697  f0rn0  5325  fliftfun  5705  th3qlem1  6539  enq0ref  7265  enq0tr  7266  genpdisj  7355  addlsub  8156  fsum2dlemstep  11235  0dvds  11549  cncongr1  11820
  Copyright terms: Public domain W3C validator